case condition and sum()公共表表达式或分组依据

bhmjp9jg  于 2021-07-24  发布在  Java
关注(0)|答案(1)|浏览(350)

希望有人能帮忙?我有一个第三方软件,我可以做自定义sql查询,但不能改变任何数据库。努力得到我想要的结果。
我是否使用group by或cte来获得我需要的结果?

WITH CTE AS ( 
SELECT  tblTicketsSummary.fldDateScheduled AS [Scheduled], 
tblTicketsRow.fldStartTime  AS [TIME], tblTicketsRow.fldPs AS 
[s],tblTicketsRow.fldPrice AS PR, 
tblTicketsSummary.fldFirstName+' '+tblTicketsSummary.fldLastName 
AS [Client], ROW_NUMBER() OVER 
(PARTITION BY tblTicketsSummary.fldTicketID ORDER BY 
tblTicketsRow.fldTicketID) AS C, tblTicketsSummary.fldDateClosed 
AS [Date Closed],
 CASE WHEN tblTicketsRow.fldPs ='p' THEN tblTicketsRow.fldPrice  
ELSE £0.00 END AS Product,  
CASE WHEN tblTicketsRow.fldPs ='s' THEN tblTicketsRow.fldPrice  
ELSE £0.00 END AS Services, 
FROM tblTicketsSummary INNER JOIN 
tblTicketsRow ON tblTicketsSummary.fldTicketID = tblTicketsRow.fldTicketID
 WHERE (fldDateVoided IS NULL) AND (NOT(fldDateClosed IS NULL)) 
GetUserDate('AND','fldDateClosed','') AND tblTicketsRow.fldEmployeeName ='Tina Young' 
 AND tblTicketsSummary.fldTotal >1 )
SELECT * FROM  CTE   ORDER BY   Scheduled ASC,  TIME ASC

这给了我下面的结果。我已经删除了在最后一个select中的c=1,我将把它放回最终的查询中,这个查询会在我想要的时候给出第一个结果。我正在挣扎的是。我想把所有产品的价格加在一起,把所有服务的价格加在一起,得出销售的产品和服务的总数。然后将服务和产品总计在一起进行最终查询。

Scheduled   TIME s   PR      Client   C Date Closed Product  Services  Total
17/07/2020 17:00 S £10.00 Ben Preston 1 17/07/2020  £0.00    £10.00     s+p
17/07/2020 17:45 S £1.00  Ben Preston 2 17/07/2020  £0.00    £1.00      s+p
17/07/2020       P £19.00 Ben Preston 3 17/07/2020  £19.00   £0.00      s+p
17/07/2020       P £10.00 Ben Preston 4 17/07/2020  £10.00   £0.00      s+p

我想要的结果如下。查询的最后一部分如下所示。我只能在第三方软件中自定义查询。

SELECT * FROM  CTE  WHERE c=1 ORDER BY   Scheduled ASC,  TIME ASC 

Scheduled  TIME   Client       C   Date Closed  Product Services   Total
17/07/2020 17:00 Ben Preston   1   17/07/2020   £29.00   £11.00    £40.00

我希望我已经格式化了这个权利,让人们理解。谢谢你的帮助。

tp5buhyn

tp5buhyn1#

似乎您只需在现有cte中添加两个组和,然后将它们添加到最终选择中:

WITH CTE AS ( 
SELECT  tblTicketsSummary.fldDateScheduled AS [Scheduled], 
   tblTicketsRow.fldStartTime  AS [TIME], 
   tblTicketsRow.fldPs AS [s],tblTicketsRow.fldPrice AS PR, 
   tblTicketsSummary.fldFirstName+' '+tblTicketsSummary.fldLastName AS [Client], 
   ROW_NUMBER() 
   OVER (PARTITION BY tblTicketsSummary.fldTicketID
         ORDER BY tblTicketsRow.fldStartTime) AS C, 
   tblTicketsSummary.fldDateClosed AS [Date Closed],

   SUM(CASE WHEN tblTicketsRow.fldPs ='p' THEN tblTicketsRow.fldPrice ELSE £0.00 END)
   OVER (PARTITION BY tblTicketsSummary.fldTicketID) AS Product,  

   SUM(CASE WHEN tblTicketsRow.fldPs ='s' THEN tblTicketsRow.fldPrice ELSE £0.00 END)
   OVER (PARTITION BY tblTicketsSummary.fldTicketID) AS Services
FROM tblTicketsSummary
INNER JOIN tblTicketsRow
ON tblTicketsSummary.fldTicketID = tblTicketsRow.fldTicketID
WHERE (fldDateVoided IS NULL) AND (NOT(fldDateClosed IS NULL)) 
--GetUserDate('AND','fldDateClosed','') AND tblTicketsRow.fldEmployeeName ='Tina Young' 
 AND tblTicketsSummary.fldTotal >1 )
SELECT cte.*,
   Product + Services as total
FROM  CTE
WHERE C = 1
ORDER BY   Scheduled ASC,  TIME ASC;

顺便说一句 ORDER BY tblTicketsRow.fldTicketID 在您的行上,行号不是基于唯一的列,因此不能保证行的顺序。你可能想要 order by tblTicketsRow.fldStartTime 相反。

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