我正在使用带有kotlin和postgresql的spring boot作为db。对于我使用的json字段 hibernate-types-52 :

dependencies {
    ...
    implementation("com.vladmihalcea:hibernate-types-52:2.10.2")
    ...
}

我有一个实体地址和street json字段：

@Entity
@Table(name = "addresses")
@TypeDefs(
  TypeDef(name = "jsonb", typeClass = JsonBinaryType::class),
  TypeDef(name = "json", typeClass = JsonStringType::class),
)
data class Address(

  @Id
  var id: Int? = null,

  @Type(type = "jsonb")
  @Column(name = "street", columnDefinition = "json", nullable = false)
  var street: Map<Language, String>,

  @Column(name = "zip_code" nullable = false)
  var zipCode: String,

  @Column(name = "created_at", nullable = false, updatable = false)
  @CreationTimestamp
  var createdAt: Date? = null,

  @Column(name = "updated_at", nullable = false)
  @UpdateTimestamp
  var updatedAt: Date? = null,
}

相应的存储库是：

@Repository
interface AddressRepository : JpaRepository<Address, Int> {

    fun findStreetByZipCode(zipCode: String): AddressStreetOnly?
}

其中addressstreetonly是一个接口：

interface AddressStreetOnly {
    val id: Int
    val street: Map<Language, String>
}

语言是一种枚举 enum class Language { EN, RU, KZ, TJ } 问题是我打电话的时候 findStreetByZipCode 基础sql语句在select查询中包含所有字段：

select
    address0_.id as id1_9_,
    address0_.created_at as created_2_9_,
    address0_.street as street3_9_,
    address0_.updated_at as updated4_9_,
    address0_.zip_code as zip_cod5_9_
from
    addresses
where
    address0_.zip_code = ?

但如果我改变了 val street: Map<Language, String> 在addressstreetonly接口中键入 val street: Any ，一切正常：

select
    address0_.id as col_0_0_,
    address0_.street as col_1_0_
from
    addresses
where
    address0_.zip_code = ?

我认为问题出在street字段的类型上，它是map，它迫使map获取实体的所有字段。我怎样才能解决这个问题？