我编写了一个方法,但收到了一个错误。这是我的密码:
def workouts_number
@workout_block = BlockWorkout.all
@number = Hash.new(0)
@workout_block.each do |record|
@current_workout_block = BlockWorkout.group(:workout_id).order(COUNT(workout_id) DESC).limit(5)
@name = @current_workout_block['block_name']
@number[@name] += 1
end
render :json => {data: {unprocessed: @workout_block, processed: @number}}
end
然后我收到了这个错误消息:
{
"status": 500,
"error": "Internal Server Error",
"exception": "#<SyntaxError: /home/gabriel_rc/Área de Trabalho/Atlas/atlas-academia-back/app/controllers/workouts_controller.rb:146: syntax error, unexpected tCONSTANT, expecting ')'\n...d).order(COUNT(workout_id) DESC).limit(5)\n... ^~~~\n/home/gabriel_rc/Área de Trabalho/Atlas/atlas-academia-back/app/controllers/workouts_controller.rb:174: syntax error, unexpected end, expecting end-of-input>",
"traces": {
"Application Trace": [
{
"exception_object_id": 27087800,
"id": 0,
"trace": "app/controllers/workouts_controller.rb:146: syntax error, unexpected tCONSTANT, expecting ')'"
},
它说在第146行发生了语法错误。第146行如下:
@current_workout_block = BlockWorkout.group(:workout_id).order(COUNT(workout_id) DESC).limit(5)
我怎样才能解决这个问题?
1条答案
按热度按时间pgpifvop1#
只需在sql片段周围添加引号,这样ruby就可以将其作为字符串处理。