我有一个表,它有两列:“timestart”和“timefinish”。这些列存储一个长值,该值使用typeclassconverter从日期格式转换而来。
我需要编写一个查询来返回表中的所有行,但我需要计算总时间。因此,我需要减去timestart和timefinish中的long值,以获得每行花费的时间,然后将它们相加。我想返回一个以小时为单位的值,让用户知道他们花了多少小时做活动。我不知道做这件事最好的方法是什么。有人能帮我写一个具有上述功能的查询吗?
table
@Entity(tableName = "tableCheckIn")
public class TableCheckIn {
@PrimaryKey(autoGenerate = true)
private long pkCheckInId;
@ColumnInfo(name = "userId")
private long fkUserId;
@ColumnInfo(name = "moodStart")
private long moodStart;
@ColumnInfo(name = "checkInChallenge")
private String checkInChallenge;
@ColumnInfo(name = "checkInGratitude")
private String checkInGratitude;
@ColumnInfo(name = "workoutStart")
@TypeConverters({TimeTypeConverter.class})
private Date workoutStart;
@ColumnInfo(name = "workoutEnd")
@TypeConverters({TimeTypeConverter.class})
private Date workoutEnd;
日期转换器
public class TimeTypeConverter {
@TypeConverter
public static Long toDate(Date date){
return date == null ? null : date.getTime();
}
@TypeConverter
public static Date toLong(Long timestamp){
return timestamp == null ? null : new Date(timestamp);
}
刀
@Query("SELECT (SUM(workoutEnd - workoutStart) / 3600) as totalWorkouts FROM tableCheckIn WHERE userId = :pkUserId")
LiveData<List<ModelStatsTotalWorkoutTime>> totalWorkoutTime(long pkUserId);
回购
public LiveData<List<ModelStatsTotalWorkoutTime>> totalWorkoutTime(long userId) {
return feelingFitDatabase.getUsersDao().totalWorkoutTime(userId);
}
视图模型
public LiveData<List<ModelStatsTotalWorkoutTime>> totalWorkoutTime(long userId) {
return repoUsers.totalWorkoutTime(userId);
}
片段
mViewModelUsers.totalWorkoutTime(pkUserId).observe(getViewLifecycleOwner(), new Observer<List<ModelStatsTotalWorkoutTime>>() {
@Override
public void onChanged(List<ModelStatsTotalWorkoutTime> modelStatsTotalWorkouts) {
for(ModelStatsTotalWorkoutTime list: modelStatsTotalWorkouts){
totalWorkoutTimeSeconds += list.getTotalWorkouts();
}
totalWorkoutTimeMinutes = totalWorkoutTimeSeconds / 60;
totalWorkoutTimeHours = totalWorkoutTimeMinutes / 60;
if (totalWorkoutTimeMinutes <= 59){
tvTotalTimeWorkingOut.setText(""+totalWorkoutTimeMinutes);
tvTotalTimeWorkingOutDescription.setText(getString(R.string.workout_minutes));
} else {
tvTotalTimeWorkingOut.setText(""+totalWorkoutTimeHours);
tvTotalTimeWorkingOutDescription.setText(getString(R.string.workout_hours));
}
}
});
}
1条答案
按热度按时间jgovgodb1#
列
TimeStart
以及TimeFinish
包含包含毫秒的unix历元时间戳。在sqlite中,您可以使用以下命令以可读格式获取日期:
返回:
要获得它们在分钟内的差异,必须除以1000以去除毫秒,然后再除以60:
因此,您可以在几分钟内获得总差异: