我有一个名为user\u info的表
它有两列：

User_id
Date

我怎样才能坐到下面提到的那张table上：

----------------------------------------------------------------
Date        |total_number_of_users | D2    |D5  |  D7 |   D14|
--------------------------------------------------------------
2020-07-01      1000                 700    500   200    150
2020-07-02      400                  300    250   200    100

例如，考虑我试图实现的表中的第一行：

total_number_of_users = Total number of users who have visited the site on 2020-07- 01

d2=在2020-07-01访问网站的用户总数中，在2020-07-2访问

D7=Out of total users who visited the site on 2020-07-01, visited on 2020-07-7

我尝试了以下方法，如何得到精确解：

SELECT user_id, week(login_date) AS login_week
    FROM user_info
    GROUP BY user_id,week(login_date);
SELECT user_id, min(week(login_date)) AS first_week
       FROM user_info
       GROUP BY user_id;
select a.user_id,a.login_week,b.first_week as first_week  from   
              (SELECT
                user_id,
                week(login_date) AS login_week
                FROM user_info
                GROUP BY user_id,week(login_date)) a,
              (SELECT
                user_id,
                min(week(login_date)) AS first_week
                FROM user_info
                GROUP BY user_id) b
        where a.user_id=b.user_id;