首先,让我们定义表:
CREATE TABLE dbo.Reviews (
id int IDENTITY(1,1) NOT NULL PRIMARY KEY,
reviewer char(64) NOT NULL,
reviewee char(64) NOT NULL,
review_date datetime NOT NULL,
)
CREATE TABLE dbo.Questions (
id int IDENTITY(1,1) NOT NULL PRIMARY KEY,
question_name varchar(255) NOT NULL,
question_description varchar(500) NOT NULL,
input_type_id int NOT NULL,
option_group_id INT NULL
)
CREATE TABLE dbo.Input_Types (
id int IDENTITY(1,1) NOT NULL PRIMARY KEY,
input_type_name varchar(80) NOT NULL
)
CREATE TABLE dbo.Option_Groups (
id int IDENTITY(1,1) NOT NULL PRIMARY KEY,
option_group_name varchar(45) NOT NULL
)
CREATE TABLE dbo.Option_Choices (
id int IDENTITY(1,1) NOT NULL PRIMARY KEY,
option_group_id int NOT NULL,
option_choice_name varchar(45) NULL,
option_choice_value int NULL
)
CREATE TABLE dbo.Answers (
id int IDENTITY(1,1) NOT NULL PRIMARY KEY,
review_id int NOT NULL,
question_id int NULL,
answer_numeric int NULL,
answer_text varchar(max) NULL,
answer_yn bit NULL
)
ALTER TABLE Answers WITH CHECK ADD FOREIGN KEY(question_id) REFERENCES Questions (id)
ALTER TABLE Answers WITH CHECK ADD FOREIGN KEY(review_id) REFERENCES Reviews (id)
ALTER TABLE Option_Choices WITH CHECK ADD FOREIGN KEY(option_group_id) REFERENCES Option_Groups (id)
ALTER TABLE Questions WITH CHECK ADD FOREIGN KEY(input_type_id) REFERENCES Input_Types (id)
ALTER TABLE Questions WITH CHECK ADD FOREIGN KEY(option_group_id) REFERENCES Option_Groups (id)
以下查询获取特定被审核人的所有答案和问题:
SELECT r.review_date, s1.q_id, s1.question_description, s1.answer_numeric
FROM Reviews r
LEFT JOIN (SELECT a.review_id, q.id q_id ,q.question_description, a.answer_numeric
FROM Answers a
LEFT JOIN Questions q
ON a.question_id=q.id
WHERE a.answer_numeric IS NOT NULL
AND a.question_id IS NOT NULL) s1
ON r.id=s1.review_id
WHERE r.reviewee = 'SOMEUNIQUEIDGOESHERE'
输出大致如下:
review_date q_id question_description answer_numeric
-----------------------------------------------------------------
2020-06-15 09:59:21.677 27 Role models blah 2
2020-06-15 09:59:21.677 29 Looks for blah 3
2020-06-15 09:59:21.677 30 Consistently blah 2
2020-06-26 13:58:58.420 27 Role models blah 5
2020-06-26 13:58:58.420 29 Looks for blah 4
2020-06-26 13:58:58.420 30 Consistently blah 4
我想要的是这样的输出:
q_id question_description 2020-06-15 2020-06-26
---------------------------------------------------
27 Role models blah 2 5
29 Looks for blah 3 4
30 Consistently blah 2 4
问题和评论/评论的数量直到运行时才知道。
我最终将为vb/asp前端编写这个查询,因此如果通过vb处理一些动态信息更容易,那是可行的。它不一定是一个纯粹的sql解决方案。
编辑我尝试了以下查询:
DECLARE @cols AS VARCHAR(MAX), @query AS VARCHAR(MAX)
SELECT @cols = STUFF((SELECT ',', QUOTENAME(review_date) FROM Reviews WHERE reviewee = '9AA1D3BAE1E0A9FA27B4857992548665C252931263B4D407CA8BBF21DC08D800' FOR XML PATH (''), TYPE).value('.', 'VARCHAR(MAX)'),1,1,'')
SET @query = 'SELECT q_id, question_description, ' + @cols + ' FROM
(SELECT r.review_date, s1.q_id, s1.question_description, s1.answer_numeric
FROM Reviews r
LEFT JOIN (SELECT a.review_id, q.id q_id ,q.question_description, a.answer_numeric
FROM Answers a
LEFT JOIN Questions q
ON a.question_id=q.id
WHERE a.answer_numeric IS NOT NULL
AND a.question_id IS NOT NULL) s1
ON r.id=s1.review_id
WHERE r.reviewee = ''UNIQUEIDGOESHERE''
) x
PIVOT
(
SUM(answer_numeric)
FOR review_date IN (' + @cols + ')
) P
ORDER BY q_id'
execute(@query);
它创建了正确的列,但日期列中的结果为null
1条答案
按热度按时间ax6ht2ek1#
好吧,最后一个查询结果是正确的,问题是从quotename隐式发生的自动日期到字符串转换导致in子句中没有匹配项。
最终正确查询: