查看联接：https://www.w3schools.com/sql/sql_join.asp
您的基本意思是您需要一个sql语句和一个while循环（如果我理解正确的话）

<?
$condition=$core_db->Execute("select * FROM table1 
INNER JOIN table2 ON table2.id = table1.id");

echo 'any';
while(!$condition->EOF){   
    echo 'any';
    $condition->MoveNext();
};

?>

更新：
根据您的更新：

$condition1=$core_db->Execute("select Husbandname, age, 
marriedto from husbands");
$condition2=$core_db->Execute("select age, 
marriedto from wifes where wifename=?", array($condition1->fields[2]));

我会这样做（sql方式）：

$condition = $core_db->Execute("select husbands.Husbandname, 
husbands.age, husbands.marriedto, wifes.id, wifes.age, wifes.marriedto from 
husbands INNER JOIN husbands.marriedto = wifes.id");

while(!$condition->EOF){   
    echo 'any';
    $condition->MoveNext();
};

如果你想用php而不是sql来实现这一点，你可以这样做（我推荐sql-way）

<?
$condition1=$core_db->Execute("select Husbandname, age, 
marriedto from husbands");

echo 'any';
while(!$condition1->EOF){   
    $condition2=$core_db->Execute("select age, 
    marriedto from wifes where wifename=?", array($condition1->fields[2]));

    echo 'any';
    $condition1->MoveNext();
};

?>

你的意思是这样的：

<?
  $condition1=$core_db->Execute("select ANY from Any");
  $condition2=$core_db->Execute("select ANY from Any");

        while(!$condition1->EOF || !condition2->EOF){   
            if (!$condition1->EOF) {
                // Code for condition1...
                $condition1->MoveNext();
            }
            if (!$condition2->EOF) {
                // Code for condition2...
                $condition2->MoveNext();
            }
        };
?>

但这通常不是正确的方法（在一个循环中处理查询）