我有以下疑问:
SELECT "factures"."id"
FROM "factures"
WHERE ( "factures"."id" NOT IN (SELECT DISTINCT( "echeances"."facture_id" )
FROM "echeances"
WHERE "echeances"."type_decheance" IN ( 2, 3, 4, 5, 8, 9 )
AND "echeances"."facture_id" IS NOT NULL
LIMIT 100000)) <----- removing this limit makes the query take enormous time
ORDER BY "factures"."id" DESC
以下是限制为100000的解释分析:
Index Only Scan Backward using factures_id_pkey on factures (cost=93516.76..211292.17 rows=530570 width=4) (actual time=1425.701..11466.759 rows=963698 loops=1)
Filter: (NOT (hashed SubPlan 1))
Rows Removed by Filter: 99997
Heap Fetches: 1063695
SubPlan 1
-> Limit (cost=0.43..93266.34 rows=100000 width=4) (actual time=0.022..1229.925 rows=100000 loops=1)
-> Unique (cost=0.43..264837.37 rows=283959 width=4) (actual time=0.022..1090.692 rows=100000 loops=1)
-> Index Scan using echeances__facture_id__idx on echeances (cost=0.43..262883.29 rows=781631 width=4) (actual time=0.020..819.735 rows=100167 loops=1)
Index Cond: (facture_id IS NOT NULL)
" Filter: (type_decheance = ANY ('{2,3,4,5,8,9}'::integer[]))"
Rows Removed by Filter: 156995
Planning time: 0.249 ms
Execution time: 11960.423 ms
以下是无限制的解释:
-> Unique (cost=0.43..264837.37 rows=283959 width=4)
Index Only Scan Backward using factures_id_pkey on factures (cost=0.86..142233669403.15 rows=530570 width=4)
Filter: (NOT (SubPlan 1))
SubPlan 1
-> Materialize (cost=0.43..267367.16 rows=283959 width=4)
-> Index Scan using echeances__facture_id__idx on echeances (cost=0.43..262883.29 rows=781631 width=4)
Index Cond: (facture_id IS NOT NULL)
" Filter: (type_decheance = ANY ('{2,3,4,5,8,9}'::integer[]))"
这是模式
Table "factures"
id
Table "echeances"
id
facture_id (fk)
type_decheance (integer)
问题是“factures”和“echeances”表有大量的行,如果:
子查询中指定了limit,例如limit 100000,查询时间很快
在子查询中没有指定限制,这需要很多时间,我不得不在等待了15分钟之后停止它。
我们的目标是在合理的时间内无限制地运行这个查询。
1条答案
按热度按时间ttisahbt1#
切换到
NOT EXISTS
:注意,我删除了所有的双引号。不要引用你的标识符。它只会使查询更难写和读。
然后你需要一个索引
echeances(facture_id, type_decheance)
. 这应该很快,因为每个facture id都可以通过简单的索引查找进行检查。