我正在制作一个控制esp模块的应用程序,我正在使用okhttpclient发出post web请求。您可以在设置选项卡中设置esp模块的ip(例如,如果您的esp ip为123.456.789,则web请求的url为http://123.456.789),我正在使用SharedReferences将设置活动中的数据保存、加载并获取到主活动中,但当我打开应用程序时,它会崩溃,错误url==null。
我让它工作的唯一方法是加载如下内容:
public String ip = SettingsActivity.ipEsp;
但是,每次我重新打开应用程序时,我都必须打开要加载数据的设置活动。(尝试使用SharedReferences保存此值,但它似乎不起作用,没有崩溃或任何不起作用的东西)
我想让它以某种方式保存,这样每当我重新打开应用程序时,它就会记住我在设置中设置的ip地址。
以下是主要活动代码:
public class MainActivity extends AppCompatActivity {
Button settings;
Button send;
TextView view;
TextView see;
public String urlS;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
settings = (Button) findViewById(R.id.button);
send = (Button) findViewById(R.id.button2);
view = (TextView) findViewById(R.id.textView);
see = (TextView) findViewById(R.id.see);
SharedPreferences urls = getSharedPreferences("sPrefs", MODE_PRIVATE);
urlS = urls.getString("url", "http://0.0.0.0:8888");
send.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
client.newCall(requestlL).enqueue(new Callback() {
@Override
public void onFailure(Call call, IOException e) {
}
@Override
public void onResponse(Call call, Response response) throws IOException {
if (response.isSuccessful()){
String myR = response.body().string();
MainActivity.this.runOnUiThread(new Runnable() {
@Override
public void run() {
see.setText(myR);
}
});
}
}
});
view.setText(urlS);
}
}
);
settings.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
setting();
}
});
}
OkHttpClient client = new OkHttpClient();
String urllL = urlS;
Request requestlL = new Request.Builder()
.url(urllL)
.build();
public void setting() {
Intent intent = new Intent(this, MainActivity2.class);
startActivity(intent);
}
}
这是设置活动代码:
public class MainActivity2 extends AppCompatActivity {
private Handler sHand = new Handler();
public static final String S_PREFS = "sPrefs";
public static final String URL = "url";
Button back;
Button save;
EditText url;
public String urlS;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main3);
back = (Button) findViewById(R.id.button3);
save = (Button) findViewById(R.id.button4);
url = (EditText) findViewById(R.id.edit);
back.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
back();
}
});
save.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
urlS = url.getText().toString();
save();
}
});
load();
view();
}
public void back()
{
Intent intent = new Intent(this, MainActivity.class);
startActivity(intent);
}
public void saveDataRunS()
{
sHand.post(saveDs);
}
private Runnable saveDs= new Runnable() {
@Override
public void run() {
save();
load();
sHand.postDelayed(this, 1);
}
};
public void save()
{
SharedPreferences sharedPreferences = getSharedPreferences("sPrefs", MODE_PRIVATE);
SharedPreferences.Editor edit = sharedPreferences.edit();
edit.putString(URL, url.getText().toString());
edit.apply();
}
public void load()
{
SharedPreferences sharedPreferences = getSharedPreferences(S_PREFS, MODE_PRIVATE);
urlS = sharedPreferences.getString(URL, "http://0.0.0.0:8888");
}
public void view()
{
url.setText(urlS);
}
}
这就是我得到的错误:
E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.example.test, PID: 18146
java.lang.RuntimeException: Unable to instantiate activity ComponentInfo{com.example.test/com.example.test.MainActivity}: java.lang.NullPointerException: url == null
at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:3222)
at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:3437)
at android.app.servertransaction.LaunchActivityItem.execute(LaunchActivityItem.java:83)
at android.app.servertransaction.TransactionExecutor.executeCallbacks(TransactionExecutor.java:135)
at android.app.servertransaction.TransactionExecutor.execute(TransactionExecutor.java:95)
at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2041)
at android.os.Handler.dispatchMessage(Handler.java:107)
at android.os.Looper.loop(Looper.java:214)
at android.app.ActivityThread.main(ActivityThread.java:7386)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:492)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:980)
Caused by: java.lang.NullPointerException: url == null
at okhttp3.Request$Builder.url(Request.java:132)
at com.example.test.MainActivity.<init>(MainActivity.java:99)
at java.lang.Class.newInstance(Native Method)
at android.app.AppComponentFactory.instantiateActivity(AppComponentFactory.java:95)
at androidx.core.app.CoreComponentFactory.instantiateActivity(CoreComponentFactory.java:45)
at android.app.Instrumentation.newActivity(Instrumentation.java:1250)
at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:3210)
at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:3437)
at android.app.servertransaction.LaunchActivityItem.execute(LaunchActivityItem.java:83)
at android.app.servertransaction.TransactionExecutor.executeCallbacks(TransactionExecutor.java:135)
at android.app.servertransaction.TransactionExecutor.execute(TransactionExecutor.java:95)
at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2041)
at android.os.Handler.dispatchMessage(Handler.java:107)
at android.os.Looper.loop(Looper.java:214)
at android.app.ActivityThread.main(ActivityThread.java:7386)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:492)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:980)
1条答案
按热度按时间gopyfrb31#
@leeo6002在mainactivity2中,save()方法的调用方式如下。oncreate->savedataruns->shand.post(saveds)->save->edit.putstring(url,url.gettext().tostring());
基本上,只要触发活动的oncreate,就可以从url edittext获取值。这意味着您没有等待用户在edittext中输入值。至少,这是问题之一。
老实说,你需要清理你的代码,它现在是一个很大的混乱。