我一直试图在我的申请表提交,但我不断得到以下错误 2021-07-05 21:40:38.910[0;39m [33m WARN[0;39m [35m18360[0;39m [2m---[0;39m [2m[nio-8080-exec-3][0;39m [36m.w.s.m.s.DefaultHandlerExceptionResolver[0;39m [2m:[0;39m Resolved [org.springframework.beans.TypeMismatchException: Failed to convert value of type 'java.lang.String' to required type 'com.issuetracking.app.enitities.Equipment'; nested exception is org.springframework.core.convert.ConversionFailedException: Failed to convert from type [java.lang.String] to type [java.lang.Integer] for value 'lights'; nested exception is java.lang.NumberFormatException: For input string: "lights"]
我已经这样写了我的控制器。它由显示使用表单输入的数据列表的处理程序方法组成。在表单中添加设备详细信息的处理程序方法。但是,我一直在尝试在同一页上执行此操作,以便在表单中提交数据时,数据应显示在同一页表单下方的表格中。我哪里出了问题,我如何才能做到这一点?提前谢谢。
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.PostMapping;
import com.issuetracking.app.enitities.Equipment;
import com.issuetracking.app.services.EquipmentService;
@Controller
public class EquipmentController {
private EquipmentService equipmentService;
public EquipmentController(EquipmentService equipmentService) {
super();
this.equipmentService = equipmentService;
}
@GetMapping("/equipment")
public String listEquipment(Model model) {
model.addAttribute("equipment",equipmentService.getAllEquipment());
return "equipment";
}
@GetMapping("/equipment/new")
public String addEquipment(Model model) {
Equipment equipment = new Equipment();
model.addAttribute("equipment", equipment);
return "equipment";
}
@PostMapping("/equipment")
public String saveEquipment(@ModelAttribute("equipment") Equipment equipments) {
System.out.println(equipmentService.saveEquipment(equipments));
return "redirect:/equipment";
}
}
1条答案
按热度按时间ukxgm1gy1#
基于这个错误,我会说有一个属性为“filled”的字符串值“lights”。在Map过程中,这些值不能转换为整数,因为对应的属性需要一个整数。我想说,输入对象是不正确的。