我正在定义一个具有容差的区域增长函数。我将x和y限制在图像维度内。当我使用x或y时，代码是有效的。但当我同时使用x和y时，代码会生成一个错误：

"IndexError: index 1431 is out of bounds for axis 0 with size 741"

此外，输出图像（使用x或y时）生成具有互换轴（773 x 741）的图像。图像尺寸为741 x 773。
图片：

https://drive.google.com/file/d/1wpUAAdU8DeJjp0TLY19X1FJ-xW2-JEma/view?usp=sharing

你能告诉我哪里出了错吗？
函数代码：区域\增长\平均值

def distance(a, b):
    return np.abs(int(a)-int(b))                       

# for a two-dimentional image and a single marker [x,y] position

def region_growing_average(img, img_t, tolerance, marker, m=0):

    # include this statement before applying region growing: img_t = np.zeros(img.shape)
    x = marker[0]
    y = marker[1]
    if (x+1 < img.shape[0] and x-1 >=0 and y+1 < img.shape[1] and y-1 >=0):
        img_t[x, y] = 1

        # check matrix border and conquering criterion for the 4-neigbourhood
        if (x+1 < img_t.shape[0] and img_t[x+1,y] == 0  and distance(img[x-m,y], img[x+1, y]) <= tolerance):
            region_growing_average(img, img_t, tolerance, [x+1, y], m+1)

        if (x-1 >= 0 and img_t[x-1,y] == 0  and distance(img[x+m,y], img[x-1, y]) <= tolerance):
            print(x,y, m, x+m, img[x+m,y], img[x, y+1], distance(img[x+m,y], img[x-1, y]))
            region_growing_average(img, img_t, tolerance, [x-1, y], m+1)

        if (y+1 < img_t.shape[1] and img_t[x,y+1] == 0 and distance(img[x,y-m], img[x, y+1]) <= tolerance):
            region_growing_average(img, img_t, tolerance, [x, y+1], m+1)

        if (y-1 >= 0 and img_t[x,y-1] == 0  and distance(img[x,y+m], img[x, y+1]) <= tolerance):
            region_growing_average(img, img_t, tolerance, [x, y-1], m+1)

    #It will return a binary image: img_t

img = im[:,:,2]  ##trying only one band
img_t = np.zeros(img.shape)
marker = [50,250]
region_growing_average(img, img_t, 257, marker)  #it should generate a white image