你好，我试着用Cython调用C的一个Python用户定义的回调。但是，如果不在C侧或静态函数缓冲区进行更改，看起来是不可能的。那么，绑定propper回调（ctypes和cfunctype）是否只有一个选项？
赛顿0.29.23
a、 水电站：

typedef void (*Callback) ();

class A{
    Callback callback;
public:
    A(){
       this->callback = nullptr;
    }

    void set_callback(Callback callback){
        this->callback = callback;
    }

    void call_callback(){
        this->callback();
    }
};

a、 pxd：

cdef extern from "A.hpp":
    ctypedef void (*Callback) ()
    cdef cppclass A:
        A() except +

        void set_callback(Callback callback)

        void call_callback()

b、 pyx

from A cimport A, Callback

cdef class B:
    cdef A *c_self
    cdef object callback

    def __cinit__(self):
        self.c_self = new A()

    def __dealloc__(self):
        del self.c_self

    cdef void callback_func(self) with gil:
        print("I'm here")
        self.callback()

    def set_callback(self, callback):
        self.callback = callback
        self.c_self.set_callback(<Callback>self.callback_func)

    def call_callback(self):
        self.c_self.call_callback()

def print_():
    print("hello")

b = B()
b.set_callback(print)
b.call_callback()

输出：

I'm here
[segmentation fault]

看起来像ctypes：获取c函数的实际地址是一个很好的解决方法，但它使用ctypes。这让我很害怕，但很管用：
b、 pyx

from A cimport A, Callback
import ctypes
from libc.stdint cimport uintptr_t

cdef class B:
    cdef A *c_self
    cdef object callback

    def __cinit__(self):
        self.c_self = new A()

    def __dealloc__(self):
        del self.c_self

    def set_callback(self, callback):
        f = ctypes.CFUNCTYPE(None)(callback)
        self.callback = f
        cdef Callback c_callback = (<Callback*><uintptr_t>ctypes.addressof(f))[0]
        self.c_self.set_callback(c_callback)

    def call_callback(self):
        self.c_self.call_callback()

def hello():
    print("hello")

b = B()
b.set_callback(hello)
b.call_callback()