我有json
{“照相机”：[

{
     "archives" : [
        {
           "accessPoint" : "xxxx",
           "default" : true,
           "isEmbedded" : false,
           "storage" : "xxxx",
           "storageDisplayName" : "xxxx"
        }
     ],
     "audioStreams" : [],
     "comment" : "",
     "detectors" : [
        {
           "accessPoint" : "xxxx",
           "displayName" : "",
           "events" : [ "SceneChangeDetected" ],
           "isActivated" : true,
           "parentDetector" : "",
           "type" : "xxxx"
        },
        {
           "accessPoint" : "xxxx",
           "displayName" : "",
           "events" : [ "xxx" ],
           "isActivated" : true,
           "parentDetector" : "",
           "type" : "xxxx"
        }
     ],
     "displayId" : "1",
     "displayName" : "xxx",
     "ipAddress" : "0.0.0.0",
     "isActivated" : true,
     "latitude" : "xxxx",
     "longitude" : "xxx",
     "model" : "Virtual",
     "offlineDetectors" : [],
     "ptzs" : [],
     "textSources" : [],
     "vendor" : "AxxonSoft",
     "videoStreams" : [
        {
           "accessPoint" : "xxx
        }
     ]
  },      "archives" : [

波乔
公共类allcameras{@serializedname（“cameras”）@公开私有arraylist camera；

public ArrayList<Camera> getCameras() {
    return camera;
}

public void setCameras(ArrayList<Camera> cameras) {
    this.camera = cameras;
}

公开类摄像机{@serializedname（“档案”）@公开私有arraylist档案；

@SerializedName("displayName")
@Expose
private String displayName;

public ArrayList<Archive> getArchives() {
    return archives;
}

public void setArchives(ArrayList<Archive> archives) {
    this.archives = archives;
}

public String getDisplayName() {
    return displayName;
}

public void setDisplayName(String displayName) {
    this.displayName = displayName;
}

我有一个代码，在rxjava的帮助下，我得到了这个列表。接下来，我想合并两个请求，并将执行结果（id）从一个传递到另一个
但我面临一个问题：为了让它工作，我必须一次接收一个摄影机对象，并将其id传递给另一个函数，但我只能得到一个arraylist
请帮忙，怎么办？