你可以像这样迭代每个商店的商店和书籍，

cy.get('.store').each(($store, index) => {

  const storeName = 'Store ' + index;

  cy.wrap($store, {log:false}).find('.book', {log:false})
    .then($books => {
      const titles = [...$books].map(book => {
        const available = book.classList.contains('available')
        return `${book.innerText} ${available ? '(Available)' : ''}`
      })
      return `${storeName} has these titles: ${titles.join(', ')}`
    })
    .then(cy.log)
})

哪个将注销

Store 0 has these titles: Book A (Available), Book B, Book C, Book D, Book E
Store 1 has these titles: Fiction Book, Non-Fiction Book, Comics, Manga, Poetry
Store 2 has these titles: Math, Physics, Computer Science, Biology, Chemistry

这将获得第一个存储区中的所有元素：

cy.get('.store').eq(0).find('.book')

同样，对于第二个存储区，您可以使用：

cy.get('.store').eq(1).find('.book')

为一家商店购买书籍：

cy.get('.store').eq(0).find('.book').each(($ele) => {
    cy.log($ele.text())
})

获取所有商店中的所有书籍：

cy.get('.book').each(($ele) => {
    cy.log($ele.text())
})

您可以获得所有书籍的简单数组

cy.get('.store')
    .then(elements => {
        let arrayOfBooks = []
        for (const element of elements) {
            cy.get(element)
                .find('.book')
                .each(bookElement => arrayOfBooks.push(bookElement.text()))
        }
        cy.wrap(arrayOfBooks).as('bookList')
    })

您还可以按门店号和书号获取门店对象数组

cy.get('.store')
    .then(elements => {
        let arrayOfBooks = []
        for (let i = 0; i < elements.length; i++) {
            cy.get(elements[i])
                .find('.book')
                .each((bookElement, bookIndexInStore) => {
                    arrayOfBooks.push({
                        storeNumber: i,
                        bookIndexInStore: bookIndexInStore,
                        bookName: bookElement.text()
                    })
                })
        }
        cy.wrap(arrayOfBooks).as('bookList')
    })

并在代码中进一步使用该值，如下所示：

cy.get('@bookList')
    .then(booklist => {
        //some actions with the bookList
    })