我要比较此 Dataframe df1:
Product Price
0 Waterproof Liner 40
1 Phone Tripod 50
2 Waterproof Pants 0
3 baby Kids play Mat 985
4 Hiking BACKPACKS 34
5 security Camera 160
使用df2,如下所示:
Product Id
0 Home Security IP Camera 508760
1 Hiking Backpacks – Spring Products 287950
2 Waterproof Eyebrow Liner 678897
3 Waterproof Pants – Winter Product 987340
4 Baby Kids Water Play Mat – Summer Product 111500
我想比较df1和df2中的产品列。以便找到产品的良好id。如果相似度<80,则会在id字段中输入'remove':df1和df2中产品列的文本不是100%匹配的。有人能帮我吗?或者我如何使用fuzzy wazzy获得良好的id?
这是我的密码
import pandas as pd
from fuzzywuzzy import process
data1 = {'Product1': ['Waterproof Liner','Phone Tripod','Waterproof Pants','baby Kids play Mat','Hiking BACKPACKS','security Camera'],
'Price':[40,50,0,985,34,160]}
data2 = {'Product2': ['Home Security IP Camera','Hiking Backpacks – Spring Products','Waterproof Eyebrow Liner',
'Waterproof Pants – Winter Product','Baby Kids Water Play Mat – Summer Product'],
'Id': [508760,287950,678897,987340,111500],}
df1 = pd.DataFrame(data1)
df2 = pd.DataFrame(data2)
dfm = pd.DataFrame(df1["Product1"].apply(lambda x: process.extractOne(x, df2["Product2"]))
.tolist(), columns=['Product1',"match_comp", "Id"])
我得到的是:
Product1 match_comp Id
0 Waterproof Eyebrow Liner 86 2
1 Waterproof Eyebrow Liner 50 2
2 Waterproof Pants – Winter Product 90 3
3 Baby Kids Water Play Mat – Summer Product 86 4
4 Hiking Backpacks – Spring Products 90 1
5 Home Security IP Camera 86 0
预计会是什么:
Product Price ID
0 Waterproof Liner 40 678897
1 Phone Tripod 50 Remove
2 Waterproof Pants 0 987340
3 baby Kids play Mat 985 111500
4 Hiking BACKPACKS 34 287950
5 security Camera 160 508760
1条答案
按热度按时间lp0sw83n1#
您可以创建一个 Package 器函数:
输出:
注意。输出不完全是您所期望的,您必须解释为什么应该删除第4/5行