作为实习的一部分，我正在尝试在不使用lxml的情况下使用python对网站进行数据垃圾处理，我的代码如下所示：

from urllib.request import urlopen
import requests

# Start the session

session = requests.Session()

# Create the payload

payload = {'email':'*********',
          'password':'********'
         }

# Post the payload to the site to log in

s = session.post("********************", data=payload)

url_to_scrape = "*******************"

page = urlopen(url_to_scrape)
print("printing page")
print(page)
html_bytes = page.read()
html = html_bytes.decode("utf-8")
print("printing html")
print(html)

这将返回一些网站信息，但最重要的是，没有从主要部分返回任何信息，我从主要部分收到的信息如下：

<!-- Add your site or application content here -->
  <main id="wrap" ui-view=""></main>

但我期待的是：

<main id="wrap" ui-view="" class="ng-scope"><nav class="navbar navbar-inverse ng-scope" ng-class="navColorClass" ng-controller="MainMenuController" scroll-to-top="">
  <div class="container-fluid">
    <!-- Brand and toggle get grouped for better mobile display -->
    <div class="navbar-header">
      <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#servicedesk-navbar" aria-expanded="false" ng-init="navCollapsed = true" ng-click="navCollapsed = !navCollapsed">
        <span class="sr-only">Toggle navigation</span>
        <span class="icon-bar"></span>
        <span class="icon-bar"></span>
        <span class="icon-bar"></span>
      </button>
...
...
...
...

如何获得预期的输出？