集合按分组并连接特定列laravel

eagi6jfj 于 2021-10-10 发布在 Java

关注(0)|答案(1)|浏览(376)

我有以下回应：


# items: array:4 [▼

    0 => array:6 [▼
      "taskID" => "5"
      "title" => "Idea for the Project"
      "resource" => "Fac - Architect"
      "start" => "Wed Jul 31 08:00:00 EEST 2019"
      "finish" => "Wed Jul 31 17:00:00 EEST 2019"
      "predecessors" => "-"
    ]
    1 => array:6 [▼
      "taskID" => "5"
      "title" => "Idea for the Project"
      "resource" => "Fac - PM"
      "start" => "Wed Jul 31 08:00:00 EEST 2019"
      "finish" => "Wed Jul 31 17:00:00 EEST 2019"
      "predecessors" => "-"
    ]
    2 => array:6 [▼
      "taskID" => "5"
      "title" => "Idea for the Project"
      "resource" => "King"
      "start" => "Wed Jul 31 08:00:00 EEST 2019"
      "finish" => "Wed Jul 31 17:00:00 EEST 2019"
      "predecessors" => "-"
    ]
    3 => array:6 [▼
      "taskID" => "5"
      "title" => "Idea for the Project"
      "resource" => "Stakeholder"
      "start" => "Wed Jul 31 08:00:00 EEST 2019"
      "finish" => "Wed Jul 31 17:00:00 EEST 2019"
      "predecessors" => "-"
    ]
  ]

我想将这些数组分组到一个数组中，并将资源名称连接起来，如下所示：


# items: array:4 [▼

      "taskID" => "5"
      "title" => "Idea for the Project"
      "resource" => [
          "Fac - Architect",
          "Second Resource",
           ...
        ],
      "start" => "Wed Jul 31 08:00:00 EEST 2019"
      "finish" => "Wed Jul 31 17:00:00 EEST 2019"
      "predecessors" => "-"

  ]

有什么帮助吗？如果它可以通过使用集合或数组函数而不需要使用许多for循环的方式来实现，那就太好了。我用的是拉威尔8。

php laravel laravel-8

来源：https://stackoverflow.com/questions/68542582/collection-group-by-and-concatenate-specific-column-laravel

1条答案

按热度按时间

tjrkku2a1#

不是最好的解决方案，但你可以这样做

<?php

$items = collect(YOUR_RESPONSE);
$firstItem = $items->shift();
$firstItem['resource'] = [$firstItem['resource']];

$items->reduce(function ($carry, $item) {
    $carry['resource'][] = $item['resource'];
    return $carry;
}, $firstItem);

然后 $items->all() 会给你想要的。

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集合按分组并连接特定列laravel

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