fastjson format number

gtlvzcf8  于 2021-11-27  发布在  Java
关注(0)|答案(1)|浏览(286)
System.out.printf("%.2f", 1.323);

console1.32

I use @JSONField(format = "%.2f") for Double &String &Float& BigDecimal

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.annotation.JSONField;
import lombok.Data;
import lombok.NoArgsConstructor;

import java.math.BigDecimal;

@Data
@NoArgsConstructor
public class RunTest {

    @JSONField(format = "%.2f")
    private Double d0;
    @JSONField(format = "%.2f")
    private String d1;
    @JSONField(format = "%.2f")
    private Float d2;
    @JSONField(format = "%.2f")
    private BigDecimal d3;

    public static void main(String[] args) {
        System.out.printf("%.2f", 1.323);
        RunTest runTest = JSON.parseObject("{\n" +
                "  \"d0\": 1.323,\n" +
                "  \"d1\":1.323,\n" +
                "  \"d2\": 1.323,\n" +
                "  \"d3\":1.323\n" +
                "}", RunTest.class);
    }

}

I hope value is 1.32 What should I do?

velaa5lx

velaa5lx1#

maybe don't have the method ,you can try to use deserializeUsing and write your own deserialize class

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