始终并首先检查对您的请求或/和您的soup的响应。

• 请求是否成功？
  **是否包含预期要素？
• 是否有信息表明内容被扣留？
• ..

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所以这个页面不想被刮掉，你应该尊重这一点-从技术Angular 来看，仍然可以选择访问页面及其内容，例如使用cloudscraper。

无论如何，您的find_all()的ResultSet不能被视为dict，解决方案是迭代或在本例中简单地使用find()，因为只有一个描述性元-如果属性不可用，也使用get()以避免错误：

soup.find('meta',attrs={'property':'og:description'}).get('content')

示例

import cloudscraper
from bs4 import  BeautifulSoup

kitapurl = "https://1000kitap.com/alintilar"
scraper = cloudscraper.create_scraper(browser={'browser': 'firefox','platform': 'windows','mobile': False})

response = scraper.get(url).content
soup = BeautifulSoup(response,"html.parser")
gelen_ana_veri= soup.find('meta',attrs={'property':'og:description'}).get('content')
print(gelen_ana_veri)

That is because content doesn't exist.

If you try elem = soup.find_all('meta',attrs={'property':'og:description'}) you will get nothing or an empty list []

You would also get the TypeError: list indices must be integers or slices, not str if you were to try gelen_ana_veri = soup.find_all('span',attrs={'class':'text-alt'})['content']

first check to see if the element you are looking for exists with soup.find_all() function in a more broad sense. Then if you find your element, then try to drill down more of its classes, or properties.

Here is a basic example of trying to find what you are looking for:

gelen_ana_veri = soup.find_all('meta')
print(gelen_ana_veri)

This will output a list of every meta tag and then you can see of any specific tags you are looking for.