但是，我认为只有在从服务器接收到所有数据后，分页才能工作。
你怎么会这么想？
ExtJS网格分页的工作原理是定义页面大小（比如100），然后存储告诉服务器它需要前100个条目。如果单击“下一页”，则从服务器获取第二个100个条目，依此类推。
为了使分页按预期工作，服务器API必须理解startParam、e1d1e和limitParam。

我知道现在已经很晚了，但这里有一个解决方案，适合任何想要使用extjs发送的“start”&“limit”分页参数实现django&extjs分页的人。

def fetchRecords(self, params):

    totalCount = 0
    pageNumber = 1
    records = []
    ids = []

    #Instanciate your query object
    query = Q()

    #Not really relevant for this case but in case you have any filter criteria params then put them here
    if(params.get("searchStartDate")):
         startDate = datetime.strptime(params.get("searchStartDate"), '%Y-%m-%d').date()
         query &= Q(date_created__gte=startDate)     
    if(params.get("searchEndDate")):
         endDate = datetime.strptime(params.get("searchEndDate"), '%Y-%m-%d').date()
         query &= Q(date_created__lte=endDate)     

    # Get the total count, EXT JS Grids need the total count value to be able to paginate
    totalCount = YourModel.objects.filter(query).count()

    #Get the primary keys, we do this because we don't want to get all the objects onto memory. The paginator doesn't 
    #Optimize the fetched data. If your table has millions of records and you load all the record objects to mem, the
    #execution might be quite slow
    your_model_ids_list = YourModel.objects.filter(query).order_by("-id").only('id')

    #Compute the page number based on the pagination "start" & "limit" params sent by EXT grid
    if(int(params.get("start")) != 0 ):
        pageNumber = (int(params.get("start")) / int(params.get("limit"))) + 1

    #Instanciate the paginator object with the primary keys list matching your filter criteria & limit        
    paginator = Paginator(your_model_ids_list, int(params.get("limit")))

    #Get the records that fall on the particular page number that we computed above
    recordIds = paginator.page(pageNumber)

    #Iterate through the record IDs and place them in an array list
    for recordId in recordIds.object_list:
        ids.append(recordId.id)

    #Now fetch the records from your model based on the unique ids that fall on the particular page fetched
    #above
    result = YourModel.objects.filter(Q(pk__in=ids)).order_by("-id")

    #Formulate your response object and return the data
    return {'totalCount': totalCount, 'records': result}