使用Spring Data JPA的Spring引导:无法提取结果集

rn0zuynd  于 2022-10-15  发布在  Spring
关注(0)|答案(2)|浏览(146)

我用Spring Data 开发了一个Spring引导应用程序JPA有人能解决这个问题吗我的豆子:

@Entity
@Table(name = "employee", catalog = "explorerrh")
public class Employee implements java.io.Serializable {

/**
 * 
 */
private static final long serialVersionUID = 1L;

private Integer idemployee;
private String employeeName;
private String employeeLastName;
private String employeeCin;
private String employeePhone;
private String employeeAdress;
private String employeePost;
private String employeeCnss;
private String employeeCv;
private String employeePhoto;
private String employeeSalaire;

public Employee() {
}

public Employee(String employeeName, String employeeLastName,
        String employeeCin, String employeePhone, String employeeAdress,
        String employeePost, String employeeCnss, String employeeCv,
        String employeePhoto, String employeeSalaire) {
    this.employeeName = employeeName;
    this.employeeLastName = employeeLastName;
    this.employeeCin = employeeCin;
    this.employeePhone = employeePhone;
    this.employeeAdress = employeeAdress;
    this.employeePost = employeePost;
    this.employeeCnss = employeeCnss;
    this.employeeCv = employeeCv;
    this.employeePhoto = employeePhoto;
    this.employeeSalaire = employeeSalaire;
}

@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "idemployee", unique = true, nullable = false)
public Integer getIdemployee() {
    return this.idemployee;
}

public void setIdemployee(Integer idemployee) {
    this.idemployee = idemployee;
}

@Column(name = "employeeName", length = 45)
public String getEmployeeName() {
    return this.employeeName;
}

public void setEmployeeName(String employeeName) {
    this.employeeName = employeeName;
}

@Column(name = "employeeLastName", length = 45)
public String getEmployeeLastName() {
    return this.employeeLastName;
}

public void setEmployeeLastName(String employeeLastName) {
    this.employeeLastName = employeeLastName;
}

@Column(name = "employeeCIN", length = 45)
public String getEmployeeCin() {
    return this.employeeCin;
}

public void setEmployeeCin(String employeeCin) {
    this.employeeCin = employeeCin;
}

@Column(name = "employeePhone", length = 45)
public String getEmployeePhone() {
    return this.employeePhone;
}

public void setEmployeePhone(String employeePhone) {
    this.employeePhone = employeePhone;
}

@Column(name = "employeeAdress", length = 45)
public String getEmployeeAdress() {
    return this.employeeAdress;
}

public void setEmployeeAdress(String employeeAdress) {
    this.employeeAdress = employeeAdress;
}

@Column(name = "employeePost", length = 45)
public String getEmployeePost() {
    return this.employeePost;
}

public void setEmployeePost(String employeePost) {
    this.employeePost = employeePost;
}

@Column(name = "employeeCNSS", length = 45)
public String getEmployeeCnss() {
    return this.employeeCnss;
}

public void setEmployeeCnss(String employeeCnss) {
    this.employeeCnss = employeeCnss;
}

@Column(name = "employeeCV", length = 45)
public String getEmployeeCv() {
    return this.employeeCv;
}

public void setEmployeeCv(String employeeCv) {
    this.employeeCv = employeeCv;
}

@Column(name = "employeePhoto", length = 45)
public String getEmployeePhoto() {
    return this.employeePhoto;
}

public void setEmployeePhoto(String employeePhoto) {
    this.employeePhoto = employeePhoto;
}

@Column(name = "employeeSalaire", length = 45)
public String getEmployeeSalaire() {
    return this.employeeSalaire;
}

public void setEmployeeSalaire(String employeeSalaire) {
    this.employeeSalaire = employeeSalaire;
}

}
我的服务是这样的:

interface EmployeeRepository extends Repository<Employee, Long> {

Page<Employee> findAll(Pageable pageable);

Employee findByEmployeeNameAndEmployeeCin(String employeeName, String cin);

}
然后我在com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'employee0_.employee_adress' in 'field list'上得到这个错误
我的数据库已正确生成,它与bean生成的相同!我真的不明白是什么问题!所以谁能帮我解决这个问题?谢谢你们,如果你还需要其他信息,尽管问我

aamkag61

aamkag611#

正如另一篇ij0k1l中指出的那样:
默认情况下,Spring使用org.springframework.boot.orm.jpa.SpringNamingStrategy生成表名。这是org.hibernate.cfg.ImprovedNamingStrategy的一个非常瘦的扩展。该类中的tableName方法传递了一个源String值,但它不知道它是来自@Column.name属性还是从字段名隐式生成的。
ImprovedNamingStrategy将CamelCase转换为SNAKE_CASE,因为EJB3Naming战略性只使用未更改的表名。
如果不想更改命名策略,您可以只指定小写的列名:
@Column(name="testname")
另外,您确定该列是“employeeaddress”而不是“emplyoeeaddress”吗?

5lhxktic

5lhxktic2#

确保根据数据库列名正确给出@Column(name="table_name")的所有名称。

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