如何在Groovy闭包中禁用惰性求值[duplicate]

62o28rlo 于 2022-11-01 发布在其他

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此问题在此处已有答案：

Closures in Groovy not capturing outside variables（1个答案）
四个月前关门了。
我的代码是：

def ip_list = ['192.168.1.1', '192.168.1.2', '192.168.1.3' ]
def task = [:]
for (ip in ip_list) {
   task[ip] = { println "test on ${ip}" }
}

for (f in task.values())
{
   f()
 }

输出为：

test on 192.168.1.3
test on 192.168.1.3
test on 192.168.1.3

但我期望的输出是：

test on 192.168.1.1
test on 192.168.1.2
test on 192.168.1.3

我该怎么办？
谢谢你！

groovy

来源：https://stackoverflow.com/questions/72895677/how-to-disable-lazy-evaluation-in-groovy-closure

1条答案

按热度按时间

bttbmeg01#

1

def ip_list = ['192.168.1.1', '192.168.1.2', '192.168.1.3' ]
def task = [:]
for (_ip in ip_list) {
   def ip = _ip
   task[ip] = { println "test on ${ip}" }
}

for (f in task.values())
{
   f()
}

2

def ip_list = ['192.168.1.1', '192.168.1.2', '192.168.1.3' ]
def task = [:]
for (_ip in ip_list) {
   task[_ip] = {ip-> println "test on ${ip}" }.curry(_ip)
}

for (f in task.values()){
   f()
}

3

def ip_list = ['192.168.1.1', '192.168.1.2', '192.168.1.3' ]
def task = {ip-> println "test on ${ip}" }
def task_map = ip_list.collectEntries{ip-> [ip, task.curry(ip)] }

for (f in task_map.values()){
   f()
}

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如何在Groovy闭包中禁用惰性求值[duplicate]

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