我正在尝试创建一个函数，它将在两个参数（rewrite 和 redirect）之间获得一个字符串。我无法理解。
我有一个字符串，看起来像这样：
add_header X-Robots-Tag "noindex, follow" always; rewrite ^/en/about/Administration/index.aspx /en/about/more-about/administration redirect; rewrite ^/en/about/Administration/supervisory-board/index.aspx /nl/over/meer-over/administration redirect; rewrite ^/en/about/Departments-sections-and-fields/index.aspx /en/about/more-about/department-divisions-and-fields redirect; rewrite ^/en/about/For-companies/index.aspx /en/about/more-about/for-companies redirect; rewrite ^/en/about/contact-information/index.aspx /en/about/more-about/contact-information redirect; rewrite ^/en/about/index.aspx /nl/over redirect;我需要以下输出：
/en/about/Administration/index.aspx /en/about/more-about/administration
/en/about/Administration/supervisory-board/index.aspx /nl/over/meer-over/administration
/en/about/Departments-sections-and-fields/index.aspx /en/about/more-about/department-divisions-and-fields
/en/about/For-companies/index.aspx /en/about/more-about/for-companies
/en/about/contact-information/index.aspx /en/about/more-about/contact-information
/en/about/index.aspx /nl/over什么是正确的正则表达式或方法来获取两个参数之间的所有字符串？
1条答案
按热度按时间drkbr07n1#
请尝试：
查看在线demo
\brewrite \^-在左边的单词边界和右边的空格后跟文字“^”之间按字面意思“重写”;(.*?)-匹配（惰性）0+个字符;\s+redirect;-在左侧的1+个空白字符和右侧的分号之间按字面“redirect”。查看在线GO demo，其中将打印：