使用您显示的示例，请尝试以下awk代码。

*第一个解决方案：*这考虑到您可能在单个Input_file本身中具有重复的行值，则您可以尝试以下操作：

awk '
!arr2[FILENAME,$0]++{
  arr1[$0]++
}
END{
  for(i in arr1){
    if(arr1[i]==(ARGC-1)){
       print i
    }
  }
}
' *.txt

*第二种解决方案：*此解决方案假定Input_file中没有重复项如果是这种情况，请尝试以下操作：

awk '
{
  arr[$0]++
}
END{
  for(i in arr){
    if(arr[i]==(ARGC-1)){
       print i
    }
  }
}
' *.txt

***说明：***添加上述详细说明。

awk '                      ##Starting awk program from here.
{
  arr[$0]++                ##Creating an array named arr with index of $0 and keep increasing its value.
}
END{                       ##Starting END block of this program from here.
  for(i in arr){           ##Traversing through array arr here.
    if(arr[i]==(ARGC-1)){  ##Checking condition if value of current item in arr is Equal to total number of files then print it.
       print i
    }
  }
}
' *.txt                    ##Passing all .txt files as an input to awk program from here.