我正在尝试执行从休眠到oracle表的插入操作。我的存储过程是:-
create or replace PROCEDURE ADMSN_TABLE (
P_ID NUMBER,
P_ADMISSIONFOR VARCHAR2,
P_SUBMISSIONDATE DATE, --NOT NULL
P_SUBMISSIONLASTDATE DATE --NOT NULL
)
IS
v_sno number;
BEGIN
INSERT INTO ORACLE.ADMISSION(AMSNID,ADMISSIONFOR,SUBMISSIONDATE,
SUBMISSIONLASTDATE)
VALUES (P_ID,P_ADMISSIONFOR,P_SUBMISSIONDATE,P_SUBMISSIONLASTDATE);
COMMIT;
END;
我从休眠中调用这个过程的方式:
public void callProc(){
Date utilDate= new Date();
java.sql.Date sqlDate = new java.sql.Date(utilDate.getTime());
System.out.println(sqlDate);
Date date = new Date();
SimpleDateFormat smd = new SimpleDateFormat("dd-MMM-YYYY");
String sdate = smd.format(date);
System.out.println(sdate);
try {
session = sessionFactory.openSession();
transaction = session.beginTransaction();
StoredProcedureQuery query = session.createStoredProcedureQuery("ADMSN_TABLE");
query.registerStoredProcedureParameter("P_ID", Number.class,
ParameterMode.IN);
query.registerStoredProcedureParameter("P_ADMISSIONFOR", String.class,
ParameterMode.IN);
query.registerStoredProcedureParameter("P_SUBMISSIONDATE", Date.class,
ParameterMode.IN);
query.registerStoredProcedureParameter("P_SUBMISSIONLASTDATE",Date.class,
ParameterMode.IN);
query.setParameter("P_ID", 1);
query.setParameter("P_ADMISSIONFOR", "schoolfee");
query.setParameter("P_SUBMISSIONDATE", sqlDate);
query.setParameter("P_SUBMISSIONLASTDATE", sqlDate);
query.execute();
System.out.println("excuted");
}catch(Exception ex){
ex.printStackTrace();
}
}
}
现在我尝试传递日期参数为new Date()
或sqldate
,如上面给出的。和query.setParameter("P_SUBMISSIONLASTDATE", sqlDate,TemporalType.Date);
,但它们都抛出错误:-
Caused by: org.hibernate.exception.SQLGrammarException:
Error calling CallableStatement.getMoreResults at
org.hibernate.exception.internal.SQLStateConversionDelegate.convert
(SQLStateConversionDelegate.java:106) at
org.hibernate.exception.internal.StandardSQLExceptionConverter.convert
(StandardSQLExceptionConverter.java:42) at
org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert
(SqlExceptionHelper.java:111)
at org.hibernate.result.internal.OutputsImpl.convert
at org.hibernate.result.internal.OutputsImpl.<init>
(OutputsImpl.java:55)
at org.hibernate.procedure.internal.ProcedureOutputsImpl.<init>
(ProcedureOutputsImpl.java:32)
at org.hibernate.procedure.internal.ProcedureCallImpl.buildOutputs
(ProcedureCallImpl.java:453)
at org.hibernate.procedure.internal.ProcedureCallImpl.getOutputs
(ProcedureCallImpl.java:404)
at org .hibernate.procedure.internal.ProcedureCallImpl.outputs
(ProcedureCallImpl.java:663)
at org.hibernate.procedure.internal.ProcedureCallImpl.execute
(ProcedureCallImpl.java:646)
... 41 more
Caused by: java.sql.SQLException: ORA-06550: line 1, column 7:
PLS-00306: wrong number or types of arguments in call to 'ADMSN_TABLE'
ORA-06550: line 1, column 7:
PL/SQL: Statement ignored
1条答案
按热度按时间mzmfm0qo1#
一种可能的解决方案是使用java.sql.timestamp,而不是java. sql. Date。此外,您还可以参考SQL和PL/SQL与Oracle和JDBC类型的Map,以验证数据类型Map是否正确。
这是一个如何获取java.sql.timestamp的示例