我创建了一个活动的意图，通过点击一个按钮，应该打开谷歌的地方，但它再次关闭真的很快，说没有选择的位置，并返回到主要活动，然后什么也没有发生，如果我再次点击。
我的api应该没问题，我已经检查了连接到api密钥的SHA1指纹是否正确。
结果代码为2
它在此之前的Activity中工作过，但我需要它在我单击按钮时打开，而现在当我尝试将此新Activity作为Intent打开时，它不会工作。

public class MapActivity extends AppCompatActivity {

int PLACE_PICKER_REQUEST = 1;
int status;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_events);

    status = GooglePlayServicesUtil.isGooglePlayServicesAvailable(this);
    if (status != ConnectionResult.SUCCESS) {
        if (GooglePlayServicesUtil.isUserRecoverableError(status)) {
            GooglePlayServicesUtil.getErrorDialog(status, this,
                    100).show();
        }
    }
    if (status == ConnectionResult.SUCCESS) {
        int PLACE_PICKER_REQUEST = 199;
        PlacePicker.IntentBuilder builder = new PlacePicker.IntentBuilder();
        Context context = this;
        try {
            startActivityForResult(builder.build(context), PLACE_PICKER_REQUEST);
        } catch (GooglePlayServicesRepairableException e) {
            e.printStackTrace();
        } catch (GooglePlayServicesNotAvailableException e) {
            e.printStackTrace();
        }
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    System.out.println("Result code: " + resultCode);
    System.out.println("Request code: " + requestCode);
    if (requestCode == 100) {
        status = GooglePlayServicesUtil.isGooglePlayServicesAvailable(this);
    }
    if (requestCode == 199) {

        //process Intent......
        if (data != null) {
            Place place = PlacePicker.getPlace(data, this);
            String toastMsg = String.format("Place: %s", place.getName());
            Toast.makeText(this, toastMsg, Toast.LENGTH_LONG).show();
        } else {
            String toastMsg = ("No location selected.");
            Toast.makeText(this, toastMsg, Toast.LENGTH_LONG).show();
        }

    }
}

}
这是从创建新Intent到Map的Intent

public void onClick(View view) {
        Intent i = new Intent(this, MapActivity.class);
       startActivity(i);
   }