我使用的是postgresql。
假设我有一个名为my_table
的表:
id | idcm | stores | du | au | dtc |
----------------------------------------------------------------------------------
1 | 20447 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-11-03 11:12:19.213799+01 |
2 | 20456 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-11-03 11:12:19.213799+01 |
3 | 20478 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-11-03 11:12:19.213799+01 |
4 | 20482 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-11-03 11:12:19.213799+01 |
5 | 20485 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-10-25 20:25:08.949996+02 |
6 | 20497 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-10-25 20:25:08.949996+02 |
7 | 20499 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-10-25 20:25:08.949996+02 |
我只想选择idm
的值等于stores
(该行)中数组元素之一的行。
所以我想得到这样的东西:
id | idcm | stores | du | au | dtc |
----------------------------------------------------------------------------------
2 | 20456 | [2, 5] | 2022-11-02 | 2022-11-15 | 2022-11-03 11:12:19.213799+01 |
5 | 20485 | [7, 5] | 2022-11-02 | 2022-11-15 | 2022-10-25 20:25:08.949996+02 |
6 | 20497 | [2, 6] | 2022-11-02 | 2022-11-15 | 2022-10-25 20:25:08.949996+02 |
7 | 20499 | [5, 7] | 2022-11-02 | 2022-11-15 | 2022-10-25 20:25:08.949996+02 |
我试过
select * from my_table where id in stores;
但我得到了一个语法错误。
1条答案
按热度按时间1bqhqjot1#
您需要使用
ANY()
运算子: