你可以尝试以下几种方法：

MATCH (n) 
WITH COLLECT(n) AS nodes
WITH nodes, 
size([x IN nodes WHERE x:Staff | x]) AS staff, size([x IN nodes WHERE x:Teacher | x]) AS teacher, 
size([x IN nodes WHERE x:Student | x]) AS student, size([x IN nodes WHERE x:Student AND x.avg > 7 AND x.avg < 8 | x]) AS overSeven,  
size([x IN nodes WHERE x:Student AND x.avg > 8 AND x.avg < 9 | x]) AS overEight,
size([x IN nodes WHERE x:Student AND x.avg > 9 | x]) AS overNine
RETURN { teachers: teacher, staff: staff, students: { total: student, overSeven: overSeven, overEight: overEight, overNine: overNine }}

在这里，我们提取所有节点并将它们收集到列表中，然后在筛选元素后计算列表的大小，匹配一定的条件。例如：
size([x IN nodes WHERE x:Staff | x])
此语句计算列表的大小，其中只存在staff节点。