如何在DB2中更新或插入到同一个表中

w80xi6nr  于 2022-11-07  发布在  DB2
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我尝试在DB2(v9.7)的同一个表中更新是否存在,或者插入到是否不存在。
我有一个表“V_OPORNAC”(方案是SQLDBA),它包含三列,其中有两个主键:艾地司特(PK)、艾地泊Z(PK)、奥泊纳
我的情况是,如果IDESTE = 123456 AND IDEPOZ = 0的数据(OPONAR)不存在,则插入新行,如果存在,则更新(OPONAR)。我尝试过以下方法:

MERGE INTO SQLDBA.V_OPONAROC AS O1 
USING (SELECT IDESTE, IDEPOZ, OPONAR FROM SQLDBA.V_OPONAROC WHERE IDESTE = 123456 AND IDEPOZ = 0) AS O2
    ON (O1.IDESTE = O2.IDESTE)
WHEN MATCHED THEN
    UPDATE SET 
         OPONAR = 'test text'
WHEN NOT MATCHED THEN
    INSERT 
        (IDESTE, IDEPOZ, OPONAR) 
        VALUES (123456, 0, 'test new text')

执行上面的代码时出现此错误:

Query 1 of 1, Rows read: 0, Elapsed time (seconds) - Total: 0,013, SQL query: 0,013, Reading results: 0
Query 1 of 1, Rows read: 3, Elapsed time (seconds) - Total: 0,002, SQL query: 0,001, Reading results: 0,001
Warning:   DB2 SQL Warning: SQLCODE=100, SQLSTATE=02000, SQLERRMC=null, DRIVER=4.21.29
SQLState:  02000
ErrorCode: 100
z9zf31ra

z9zf31ra1#

通过使用“SYSIBM.SYSDUMMY1”,我发现

MERGE INTO SQLDBA.V_OPONAROC AS O1 
USING (SELECT 1 AS IDESTE, 2 AS IDEPOZ, 3 AS OPONAR FROM SYSIBM.SYSDUMMY1) AS O2
    ON (O1.IDESTE = 123456 AND O1.IDEPOZ = 0)
WHEN MATCHED THEN
    UPDATE SET 
        O1.OPONAR = 'test text'
WHEN NOT MATCHED THEN
    INSERT 
        (O1.IDESTE, O1.IDEPOZ, O1.OPONAR) 
        VALUES (123456, 0, 'test new text')

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