你可以用TypeReference来使用JacksonObjectMapper，首先你需要把它读成Map〈String，Object〉，然后你可以用Java来提取name和num。
您需要从obj中获取data，然后对于dataList中的每个项目，您必须将其Map到新的HashMap，如下所示

ObjectMapper objectMapper = new ObjectMapper ();
Map<String,Object> jsonMap = objectMapper.readValue(jsonData,new TypeReference<Map<String,Object>>(){});
List<Object> data = ((Map<String,Object>)jsonMap.get("obj")).get("data");
List<Map<String,String> result = data.stream()
   .map(d->(Map<String,Object> d)
   .map(d->{
      Map<String,String> map = new HashMap();
      map.put(d.get("name"),((Map<String,String>)d.get("value")).get("num"));
      return map;
      })
   .collect(Collectors.toList());

但是，如果您可以为数据创建一个class，则会更容易一些。

库 * 乔森 * 可以胜任这项工作。
https://github.com/octomix/josson
还原序列化

Josson josson = Josson.fromJsonString(
    "{" +
    "  \"code\": 1," +
    "  \"msg\": \"query success\"," +
    "  \"obj\": {" +
    "    \"data\": [" +
    "      {" +
    "        \"name\": \"\"," +
    "        \"value\": {" +
    "          \"num\": \"89\"" +
    "        }" +
    "      }," +
    "      {" +
    "        \"name\": \"1\"," +
    "        \"value\": {" +
    "          \"num\": \"19\"" +
    "        }" +
    "      }," +
    "      {" +
    "        \"name\": \"2\"," +
    "        \"value\": {" +
    "          \"num\": \"6\"" +
    "        }" +
    "      }" +
    "    ]" +
    "  }," +
    "  \"success\": true," +
    "  \"duration\": 523" +
    "}");

转型

JsonNode node = josson.getNode("obj.data.map(name::value.num)");
System.out.println(node);

List<Map<String, String>> result = Josson.readValueFor(node, List.class);
System.out.println(result);

输出量

[{"":"89"},{"1":"19"},{"2":"6"}]

[{=89}, {1=19}, {2=6}]