键保证是唯一的，所以最后，我只需要一个平面Map。另外，我不需要将TransactionInfo序列化回JSON。

由于所有键都是唯一的，并且您不关心将此POJO序列化回JSON，因此可以将Map列表转换为构造函数中的 map。

public class TransactionInfo {
    String transactionId;
    Boolean isSettled;
    Map<String, String> transactionProperties;

    public TransactionInfo(String transactionId, Boolean isSettled, Map<String, String> transactionProperties) {
        this.transactionId = transactionId;
        this.isSettled = isSettled;
        this.transactionProperties = transactionProperties;
    }

    public TransactionInfo(
        @JsonProperty("transactionId") String transactionId,
        @JsonProperty("isSettled") Boolean isSettled,
        @JsonProperty("transactionProperties") List<Map<String, String>> transactionPropertiesList) {

        this.transactionId = transactionId;
        this.isSettled = isSettled;
        this.transactionProperties = transactionPropertiesList.stream()
            .flatMap(map -> map.entrySet().stream())
            .collect(Collectors.toMap(
                Map.Entry::getKey,
                Map.Entry::getValue
            ));
    }
}

main()的代码片段：

String json = """
            {
               "transactionId": "EFODKKXHE003",
               "isSettled": false,
               "transactionProperties": [
                 {
                   "key1": "Value1"
                 },
                 {
                   "key2": "Value2"
                 },
                 {
                   "key3": "Value3"
                 }
               ]
             }""";

ObjectMapper mapper = new ObjectMapper();
TransactionInfo transactionInfo = mapper.readValue(json, TransactionInfo.class);
System.out.println(transactionInfo);

• 输出：*

TransactionInfo{transactionId='EFODKKXHE003', isSettled=false, transactionProperties={key1=Value1, key2=Value2, key3=Value3}}

一种选择是将transactionProperties字段的类型更改为List<ObjectNode>，然后遍历列表，并对每个元素使用其fields()方法来检索其成员