我目前在android上连接Web服务时遇到问题。我使用jackson-core/databind/annotation-2.2.4和Spring RESTWebService。如果我从浏览器访问URL,我可以看到JSON响应:(服务器返回List\Shop\类似于:)
[{"name":"shopqwe","mobiles":[],"address":{"town":"city",
"street":"streetqwe","streetNumber":"59","cordX":2.229997,"cordY":1.002539},
"shoe" [{"shoeName":"addidas","number":"631744030","producent":"nike","price":999.0,
"sizes":[30.0,35.0,38.0]}]
从客户端端点(Android应用程序),我收到此错误消息:
08-26 17:43:07.406: E/AllShopsAsyc(28203): Could not read JSON: Can not deserialize
instance of com.auginzynier.data.ShopContainer out of START_ARRAY token
08-26 17:43:07.406: E/AllShopsAsyc(28203): at [Source:
com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1,
column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException:
Can not deserialize instance of com.auginzynier.data.ShopContainer out of START_ARRAY
token
08-26 17:43:07.406: E/AllShopsAsyc(28203): at [Source:
com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1,
column: 1]
08-26 17:43:07.406: E/AllShopsAsyc(28203):
org.springframework.http.converter.HttpMessageNotReadableException: Could not read
JSON: Can not deserialize instance of com.auginzynier.data.ShopContainer out of
START_ARRAY token
我的服务器请求
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
ShopContainer response = restTemplate.getForObject(url, ShopContainer.class);
其中,ShopContainer为:
public class ShopContainer {
private List<Shop> shops;
商店、地址和鞋的结构是:(我已经省略了getter和setter):
public class Shop {
@JsonProperty("name") private String name;
@JsonProperty("mobiles") private List<String> mobiles = new ArrayList<String>();
@JsonProperty("address") private Address address;
@JsonProperty("shoe") private List<Shoe> shoe = new ArrayList<Shoe>();
public class Address {
@JsonProperty("town") private String town;
@JsonProperty("street") private String street;
@JsonProperty("streetNumber") private String streetNumber;
@JsonProperty("cordX") private Double cordX;
@JsonProperty("cordY") private Double cordY;
public class Shoe {
@JsonProperty("shoeName") private String shoeName;
@JsonProperty("number") private String number;
@JsonProperty("producent") private String producent;
@JsonProperty("price") private Double price;
@JsonProperty("sizes") private List<Double> sizes = new ArrayList<Double>();
我已经在这里和谷歌上看过了,但仍然不能弄清楚我在这一点上错过了什么。
任何回应都将是非常有帮助的。
祝你好运
@更新
我已经通过使用Jackson的ObjectMapper和RequestMethod. GET修复了JSON,它现在返回一个String。
list is List<Shop>
ObjectMapper mapper = new ObjectMapper();
mapper.writeValue(new File("D:\\Android\\shop.json"), list);
System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list));
return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list);
控制台中的JSON如下所示:
[ {
"name" : "shopqwe",
"mobiles" : [ ],
"address" : {
"town" : "city",
"street" : "streetqwe",
"streetNumber" : "59",
"cordX" : 2.229997,
"cordY" : 2.002539
},
"shoe" : [ {
"shoeName" : "addidas",
"number" : "631744033",
"producent" : "nike",
"price" : 10.0,
"sizes" : [ 30.0, 35.0, 38.0 ]
} ]
} ]
请求仍然不起作用-错误是相同的。
4条答案
按热度按时间wfveoks01#
您的json包含一个数组,但您试图将其解析为一个对象。发生此错误的原因是对象必须以
{
开头。您有两个选项:
1.您可以去掉
ShopContainer
类,改用Shop[]
替换为
然后用它制作你想要的东西。
1.您可以更改服务器以返回对象而不是列表
替换为
yqkkidmi2#
如果想当然地认为您发布的JSON实际上就是您在浏览器中看到的内容,那么问题就出在JSON本身。
您发布的JSON代码段格式不正确。
您已发布:
而正确的JSON应该是:
4szc88ey3#
我在使用
spring-boot-starter-data-redis
时也遇到过类似的问题。在我的实现中,为RedisTemplate
提供了一个@Bean
,如下所示:修复方法是指定
RoutePlantCache
数组,如下所示:下面的例外我有:
50few1ms4#
在我的例子中,我有一个不正确的返回类型。返回类型是UserPost,但它应该是List,这解决了前面提到的方法