我需要刷新、重置或取消设置模型;
通常，通过使用for操作，public static $k值应该改变，并且id确实改变，但是tableName模型方法只被调用一次;
tablename的值将总是1，因为这是$i的第一个值;

for($i=1;$i<=100;$i++){
VillageBuildingKXSlaveM::$server_id = 1;
VillageBuildingKXSlaveM::$k = $i;
VillageBuildingKXSlaveM::model()->findAllByAttributes(array());
}

<?php

class VillageBuildingKXSlaveM extends VillageBuildingKXM {

    public static function model($className = __CLASS__) {
        return parent::model($className);
    }

    public static $server_id;
    public static $slave_db;
    public static $k;

    public function getDbConnection() {
        self::$slave_db = Yii::app()->dbx;
        if (self::$slave_db instanceof CDbConnection) {
            self::$slave_db->active = false;
            $config = require(Yii::app()->getBasePath() . '/config/main.php');
            $connectionString = $config['components']['dbx']['connectionString'];
            self::$slave_db->connectionString = sprintf($connectionString, self::$server_id);
            self::$slave_db->setActive(true);
            return self::$slave_db;
        } else
            throw new CDbException(Yii::t('yii', 'Active Record requires a "db" CDbConnection application component.'));
    }

    public function tableName() {
        return 'village_building_k' . self::$k;
    }

}