我需要刮多个网址同时使用scrapy和飞溅..我试着写以下代码，但仍然没有运气..
我已经附上了网址..在这里..
'下一页'，
'加利福尼亚州'，
'波士顿'
所以我需要遍历这些URL，然后使用Scrapy来抓取它。
我无法使用多个URL获取数据。它显示错误。请帮助
我的问题是如何进一步抓取这个URL列表？

import scrapy
from scrapy_splash import SplashRequest
import scrapy_proxies

class WundergroundSpider(scrapy.Spider):
    name = 'wunderground'
    #allowed_domains = ['www.wunderground.com/forecast/us/ny/brooklyn']
    start_urls = []

    script = '''
    function main(splash, args)
        splash.private_mode_enabled = false
        assert(splash:go(args.url))
        assert(splash:wait(10))
        return splash:html()
    end
    '''

    def start_requests(self):
        urls = [
        'https://wunderground.com/forecast/us/ny/brooklyn/',
        'https://www.wunderground.com/forecast/us/pa/california/',
        'https://www.wunderground.com/forecast/us/ny/boston'
        ]
        for url in urls:
            yield SplashRequest(url, self.parse,  args={'wait': 8})

    def parse(self, response):
        tmps= {
            'tempHigh': response.xpath("//div[@class='forecast']/a[@class='navigate-to ng-star-inserted']/div[@class='obs-forecast']/span/span[@class='temp-hi']/text()")[0],
            'templow': response.xpath("//div[@class='forecast']/a[@class='navigate-to ng-star-inserted']/div[@class='obs-forecast']/span/span[@class='temp-lo']/text()")[0],
            'obsphs' : response.xpath("//div[@class='forecast']/a[@class='navigate-to ng-star-inserted']/div[@class='obs-forecast']/div[@class='obs-phrase']/text()")[0]
            }
        yield tmps