import scrapy
from scrapy.crawler import CrawlerRunner

class Livescores2(scrapy.Spider):

    name = 'Home'

    def start_requests(self):
        yield scrapy.Request('https://www.livescores.com/football/turkey/super-lig/?tz=3&table=league-home')

    def parse(self, response):

        for total in response.css('td'):
            yield{
                'total': total.css('::text').get()               
                }

runner2 = CrawlerRunner()
runner2.crawl(Livescores2)

当我像下面这样调整设置时，我可以将数据保存为json，没有问题。

runner2 = CrawlerRunner(settings = {
    "FEEDS": {
    "Home.json": {"format": "json", "overwrite": True},
    },
    })

我想把返回的Scrapy数据赋给一个变量，这样我就可以处理它了。我不需要任何Json数据！
我试探着：

import scrapy
from scrapy.crawler import CrawlerRunner

class Livescores2(scrapy.Spider):

    name = 'Home'

    def start_requests(self):
        yield scrapy.Request('https://www.livescores.com/football/turkey/super-lig/?tz=3&table=league-home')

    def parse(self, response):

        for total in response.css('td'):
            yield{
                'total': total.css('::text').get()               
                }

runner2 = CrawlerRunner()
a = runner2.crawl(Livescores2) 

print(a)

结果为：〈在0x 65 cbfb 6d 0处延迟〉
如何从变量中获取数据？我开发了一个Android应用程序，所以我不需要任何Json文件。我不知道如何在此代码中使用“return”函数。
多谢了