我试着从这个网站上刮出大学的名字和链接：https://www.topuniversities.com/university-rankings/world-university-rankings/2021，在处理分页时遇到了问题，因为指向下一页的按钮的href是javascript：void（0），所以我无法使用scrapy.request（）或response.follow（）到达下一页，有没有办法处理这样的分页？
screen shot of the website
screen shot of the tag and href
这个网站的URL不包含参数，如果点击下一页按钮，URL保持不变，所以我无法通过改变URL来处理分页。
下面的代码片段只能获取第一页和第二页上的大学名称和链接：

import scrapy
from scrapy_splash import SplashRequest

class UniSpider(scrapy.Spider):
    name = 'uni'
    allowed_domains = ['www.topuniversities.com']

    script = """
    function main(splash, args)
      splash:set_user_agent("Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/101.0.4951.54 Safari/537.36")
      splash.private_mode_enabled = false
      assert(splash:go(args.url))
      assert(splash:wait(3))

      return {
        html = splash:html()
      }
    end
    """

    next_page = """
    function main(splash, args)
        splash:set_user_agent("Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/101.0.4951.54 Safari/537.36")
        splash.private_mode_enabled = false
        assert(splash:go(args.url))
        assert(splash:wait(3))

        local btn = assert(splash:jsfunc([[
        function(){
        document.querySelector("#alt-style-pagination a.page-link.next").click()
      }
        ]]))
        assert(splash:wait(2))
        btn()

        splash:set_viewport_full()
        assert(splash:wait(3))

        return {
          html = splash:html()
        }
    end
    """

    def start_requests(self):
        yield SplashRequest(
            url="https://www.topuniversities.com/university-rankings/world-university-rankings/2021",
            callback=self.parse, endpoint="execute",
            args={"lua_source": self.script})

    def parse(self, response):
        for uni in response.css("a.uni-link"):
            uni_link = response.urljoin(uni.css("::attr(href)").get())
            yield {
                "name": uni.css("::text").get(),
                "link": uni_link
            }

        yield SplashRequest(
            url=response.url,
            callback=self.parse, endpoint="execute",
            args={"lua_source": self.next_page}
        )