我有下面的查询，以获取一些数据有关两个实体在同一时间，我收到了一个错误。

@Query(value = "select new base.models.HRTableEntity( yr.user.gid,  yr.user.id,  yr.user.lastName || ' ' || yr.user.firstName,  yr.user.position,  yr.user.created,yr.genericField1,yr.genericField2) from YearlyReview yr where yr.year = :yr and yr.user.realDepartment = :dep and yr.user.city = :ct",
            countQuery = "select count(yr.id) from YearlyReview yr where yr.year = :yr and yr.user.realDepartment = :dep and yr.user.city = :ct",
            nativeQuery = false)
    Page<HRTableEntity> getAllTableEntity(Pageable pageRequest, @Param("yr") int year, @Param("dep") String department, @Param("ct") String location);

我使用默认Sort（gid: ASC）调用此函数，并收到以下错误

org.hibernate.QueryException: could not resolve property: gid of: base.entities.YearlyReview

存储库接口：

public interface PageableYearlyReview extends CrudRepository<YearlyReview, UUID>

年度考核有一个ApplicationUser类型的成员（用户），我想将信息从yr.user.gid放入HRTableEntry.gid的DTO中。
什么是正确的方法呢？
EDIT：函数调用：

crunRepoYearTable.getAllTableEntity(PageRequest.of(pageNo - 1, pageSize, sort), year, realDepartment, user.getCity())

分类建筑物

sortDir.equalsIgnoreCase(Sort.Direction.ASC.name()) ? Sort.by(sortedField).ascending() : Sort.by(sortedField).descending();

实体结构：

public class YearlyReview {
    @Id
    private UUID id;
    private int year;
    @OneToOne
    private ApplicationUser user;
....
}
public class ApplicationUser {
    @Id
    private String id;
    private String gid;
.....
}