我遇到此错误。**在提交响应后无法调用sendError()**有人能帮我找出原因吗?
@Entity
public class Product {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
@OneToOne(
fetch = FetchType.LAZY,
cascade = CascadeType.ALL
)
@JoinColumn(name = "details_id")
private Details details;
//Getters and setters left out for brevity
}
@Entity
public class Details {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int id;
private String name;
private String description;
private float price;
private float discount;
@OneToOne(mappedBy = "details")
private Product product;
}
@RestController
public class ProductController {
@Autowired
ProductRepository productRepository;
@GetMapping("/getAllProducts")
public Iterable<Product> getAllProducts(){
return productRepository.findAll();
}
}
@RestController
public class DetialsController {
@Autowired
ProductRepository productRepository;
@Autowired
DetailsRepository detailsRepository;
@PostMapping("/details")
public Details addDetails(@RequestBody Details details) {
Product newProduct = new Product();
newProduct.setDetails(details);
productRepository.save(newProduct);
return detailsRepository.save(details);
}
}
我能够对/details进行POST调用;成功添加详细信息。但当我对/getAllProducts进行GET调用时,我收到此错误在提交响应后无法调用sendError()
2条答案
按热度按时间6ovsh4lw1#
这是双向关系的一个问题,因为它们在反序列化时保持对彼此的引用,Jackson在无限循环中运行。我的第一个建议是在关系的一端添加
@JsonIgnore
。之后,如果这解决了您的问题,您可以查看@JsonManagedReference/@JsonBackReference和@JsonIdentityInfo。
您还可以查看此link以获得更多信息
9o685dep2#
您可以使用此选项: