JUnit 5异常测试JUnit 4的等效项

sqxo8psd 于 2022-11-11 发布在其他

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我有下面的JUnit 4异常测试：

@Test(expected = NotFoundException.class)
public void getRecipeByIdTestNotFound() throws Exception {

    Optional<Recipe> recipeOptional = Optional.empty();

    when(recipeRepository.findById(anyLong())).thenReturn(recipeOptional);

    Recipe recipeReturned = recipeService.findById(1L);

    //should go boom
}

我希望得到有关在JUnit 5中测试相同内容的最有效方法的帮助。

junit

来源：https://stackoverflow.com/questions/74149003/junit-5-exception-testing-equivalent-of-junit-4

1条答案

按热度按时间

7kqas0il1#

用法一：

try{
    Optional<Recipe> recipeOptional = Optional.empty(); 
    when(recipeRepository.findById(anyLong())).thenReturn(recipeOptional); 
    Recipe recipeReturned = recipeService.findById(1L);
}catch(Exception e){
    AssertThat(e, instanceOf(NotFoundException.class));
}

用法二：

Assertions.assertThrow(NotFoundException.class, () -> {
    Optional<Recipe> recipeOptional = Optional.empty();
    when(recipeRepository.findById(anyLong())).thenReturn(recipeOptional);
    Recipe recipeReturned = recipeService.findById(1L);
});

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JUnit 5异常测试JUnit 4的等效项

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