我在d3库中创建了嵌套的wheel。我不知道如何在wheel中添加文本,从里到外呈螺旋状。数字的起始点并不重要,数字必须根据之前的位置呈螺旋状向外。
代码
let allAxis = (data.map(function(i, j) {
return i.name
})),
total = allAxis.length,
radius = Math.min(options.width / 2, options.height / 2),
angleSlice = Math.PI * 2 / total,
Format = d3.format('');
let rScale = d3.scale.linear()
.domain([0, options.circles.maxValue])
.range([50, radius]);
let svg = d3.select("body").append("svg")
.attr("width", options.width + options.margins.left + options.margins.right)
.attr("height", options.height + options.margins.top + options.margins.bottom);
let g = svg.append("g")
.attr("transform", "translate(" + (options.width / 2 + options.margins.left) + "," + (options.height / 2 + options.margins.top) + ")");
let axisGrid = g.append("g")
.attr("class", "axisWraper");
let axis = axisGrid.selectAll(".axis")
.data(allAxis)
.enter()
.append("g")
.attr("class", "axis")
//append them lines
axis.append("line")
.attr("x1", 0)
.attr("y1", 0)
.attr("x2", function(d, i) {
let tempX2 = radius * Math.cos(angleSlice * i - Math.PI / 2);
return tempX2;
})
.attr("y2", function(d, i) {
let tempY = radius * Math.sin(angleSlice * i - Math.PI / 2);
return tempY;
})
.attr("class", "line")
.attr("stroke", "black")
.attr("fill", "none");
//Draw background circles
axisGrid.selectAll(".levels")
.data([12,11,10,9,8,7,6, 5, 4, 3, 2, 1])
.enter()
.append("circle")
.attr("class", function(d, i) {
return `gridCircle-${d}`
})
.attr("r", function(d, i) {
return parseInt(radius / options.circles.levels * d, 10);
})
.attr("stroke", "black")
.attr("fill-opacity", function(d, i) {
return options.circles.opacity;
});
axisGrid.select(".gridCircle-1").attr("fill-opacity", 1);
axisGrid.select(".gridCircle-2").attr("fill-opacity", 1);
预期结果
已更新#1(带有点径向)
1条答案
按热度按时间bjp0bcyl1#
您需要
pointRadial
:返回以弧度表示的给定Angular 的点[x,y],0位于-y(12点钟方向),顺时针方向为正Angular ,半径为给定半径。
您可以根据您的排列方式来调整以下示例,例如,为了从3点钟位置开始逆时针旋转等,您只需要调整
degrees
和radius
:第一个