我有一个现有的项目是在Windows和Linux上。我最近得到了一个mac的第一次，我试图设置它的C++开发，但我有一个问题，链接到curl我相信。
从我所看到的， curl 支持M1臂为基础的芯片通过自制，我安装使用homebrew install curl。
下面是我的make文件

SOURCES = DataDogStatsD.cpp DDEvent.cpp Helpers.cpp

lib_name = libDataDogStatsD.so.1.1.0.5

curl_include = /usr/local/include/curl
rapidjson_inc_path = /usr/local/include/rapidjson

OBJECTS = $(SOURCES:.cpp=.o)
CFLAGS = -fpic -c $(SOURCES) -Wall -g -Iinclude -std=c++11 -I/usr/include -I$(curl_include) -I$(rapidjson_inc_path)
CC = g++
LDFLAGS = -lpthread -pthread -lm -L/opt/homebrew/opt/curl/lib

.PHONY: clean

default:
    $(CC) -shared -Wl,-install_name,libDataDogStatsD.so.1 -o $(lib_name) $(OBJECTS) $(LDFLAGS)
    ln -sf $(lib_name) libDataDogStatsD.so

clean:
    rm -vf $(OBJECTS) depend $(lib_name)

depend: $(SOURCES)
    $(CC) $(CFLAGS) > depend

-include depend

当我运行make时，我得到以下结果：

g++ -fpic -c DataDogStatsD.cpp DDEvent.cpp Helpers.cpp -Wall -g -Iinclude -std=c++11 -I/usr/include -I/usr/local/include/curl -I/usr/local/include/rapidjson > depend
g++ -shared -Wl,-install_name,libDataDogStatsD.so.1 -o libDataDogStatsD.so.1.1.0.5 DataDogStatsD.o DDEvent.o Helpers.o -lpthread -pthread -lm -L/opt/homebrew/opt/curl/lib
Undefined symbols for architecture arm64:
  "_curl_easy_cleanup", referenced from:
      DataDogStatsD::event(DDEvent, bool, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
      DataDogStatsD::sendDDEventinthread(DDEvent, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
  "_curl_easy_getinfo", referenced from:
      DataDogStatsD::event(DDEvent, bool, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
      DataDogStatsD::sendDDEventinthread(DDEvent, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
  "_curl_easy_init", referenced from:
      DataDogStatsD::initCurl(DDEvent, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >*, curl_slist*, char const*) in DataDogStatsD.o
  "_curl_easy_perform", referenced from:
      DataDogStatsD::event(DDEvent, bool, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
      DataDogStatsD::sendDDEventinthread(DDEvent, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
  "_curl_easy_setopt", referenced from:
      DataDogStatsD::initCurl(DDEvent, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >*, curl_slist*, char const*) in DataDogStatsD.o
  "_curl_easy_strerror", referenced from:
      DataDogStatsD::event(DDEvent, bool, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
      DataDogStatsD::sendDDEventinthread(DDEvent, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
  "_curl_slist_append", referenced from:
      DataDogStatsD::initCurl(DDEvent, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >*, curl_slist*, char const*) in DataDogStatsD.o
  "_curl_slist_free_all", referenced from:
      DataDogStatsD::event(DDEvent, bool, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
      DataDogStatsD::sendDDEventinthread(DDEvent, void (*)(bool, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >)) in DataDogStatsD.o
ld: symbol(s) not found for architecture arm64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
make: *** [default] Error 1

我已经尝试将-arch设置为x86_64作为LDFLAGS上的测试，然后它成功编译并创建了库，但我真的不认为我应该在为M1构建x86_64时构建它，因此速度更快，因为它不必通过Rosetta。
如果我运行lipo -info /opt/homebrew/opt/curl/bin/curl来检查库的体系结构，我会得到以下结果：
Non-fat file: /opt/homebrew/opt/curl/bin/curl is architecture: arm64
因此curl看起来是正确的，所以不确定为什么我会得到arm 64的错误未定义符号