将curl示例转换为pycurl

ldxq2e6h 于 2022-11-13 发布在其他

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有人能把下面的PostMark curl例子转换成pycurl吗？

curl -X POST "http://api.postmarkapp.com/email" \
-H "Accept: application/json" \
-H "Content-Type: application/json" \
-H "X-Postmark-Server-Token: ed742D75-5a45-49b6-a0a1-5b9ec3dc9e5d" \
-v \
-d "{From: 'sender@example.com', To: 'receiver@example.com', Subject: 'Postmark test', HtmlBody: '<html><body><strong>Hello</strong> dear Postmark user.</body></html>'}"

curl

来源：https://stackoverflow.com/questions/22799648/convert-curl-example-to-pycurl

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按热度按时间

nom7f22z1#

你可以使用类似这样的东西，这是一个基本的实现，但是它应该可以工作。

import pycurl, json

postmark_url = 'https://api.postmarkapp.com/email'

data = json.dumps({"From": "user@example.com", "To": "receiver@example.com", "Subject": "Pycurl", "TextBody": "Some text"})

c = pycurl.Curl()
c.setopt(pycurl.URL, github_url)
c.setopt(pycurl.HTTPHEADER, ['X-Postmark-Server-Token: API_TOKEN_HERE','Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()

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将curl示例转换为pycurl

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