转换curl命令中的一些响应值

anhgbhbe  于 2022-11-13  发布在  其他
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我使用下面的脚本来获得一个特定网站的平均响应时间。它运行得很好。我只需要转换响应中的一些值,比如time_total,我想以毫秒为单位查看它,而size_download则以KB为格式。在命令的最后,我分享了平均响应时间。我也想打印它在毫秒。任何帮助是真的感谢。

for ((i=1;i<=50;i++)); do curl -w 'Return Code: %{http_code}; Bytes Received: %{size_download}; Response Time: %{time_total}\n' "https://www.google.com" -m 2 -o /dev/null -s; done |tee /dev/tty|awk '{ sum += $NF; n++ } END { If (n > 0); print "Average Response Time =",sum /n;}'
4dc9hkyq

4dc9hkyq1#

Three answer here...

As this question is tagged shell (not bash), here is three different way for doing this, by using awk + bash , shell + bc or bash alone.

1. Using awk to process output and compute averages

As doing forks like curl ... | awk ... repetitively, is resource killer, I prefer to run awkonly once, doing the whole formatting output job under awk :

iter=10
for ((i=iter;i--;));do
     curl -w '%{http_code} %{size_download} %{time_total}\n' \
         "https://www.google.com" -m 2 -o /dev/null -s
     sleep .02
done | awk -v iter=$iter '
    BEGIN {
        ttim=0;tsiz=0;
        printf "  %-3s  %8s %11s %10s\n","Res","Size","Time","Rate"
    };
    {
        printf "  %-3s  %7.2fK %9.2fms %7.2fK/s\n", \
            $1, $2/1024,$3*1000,$2/$3/1024;
        tsiz+=$2;ttim+=$3;
    };
    END {
        printf "Tot    %7.2fK %9.2fms\nAvg    %7.2fK %9.2fms %7.2fK/s\n", \
            tsiz/1024,ttim*1000, tsiz/iter/1024,ttim/iter*1000,tsiz/ttim/1024;
    }'

May produce:

Res      Size        Time       Rate
  200    14.61K    128.48ms  113.71K/s
  200    14.75K    131.06ms  112.52K/s
  200    14.73K    131.71ms  111.85K/s
  200    14.72K    130.24ms  113.05K/s
  200    14.66K    134.68ms  108.86K/s
  200    14.69K    131.39ms  111.79K/s
  200    14.63K    131.15ms  111.53K/s
  200    14.70K    126.26ms  116.42K/s
  200    14.71K    129.08ms  113.98K/s
  200    14.68K    131.23ms  111.86K/s
Tot     146.88K   1305.28ms
Avg      14.69K    130.53ms  112.53K/s

2. Working on averages using shell

As shell don't work with floating numbers, you have to use bc or another subprocess to resolv this operations.
As doing forks like var=$(echo '3*4'|bc) is resource killer, I prefer to run bc only once, as a background process. One advantage of this is bc can store overall variables (total download and total size here).

First part: Init some variables and run bc

Creating two fifos for backgrounded bc and one fifo for curl , making parsing of curl's output easier.
Declaring some variables, and numfmt function into bc for further use...
Note about numfmt : This function compute human readable presentation from integer value, output two values

  • octal character octal value of b , K , M , G , P and T and
  • floating number from submited value, divided by power of 1024

The character from octal could be output by printf '%b' \\$value under shell.

#!/bin/sh

target=${1:-https://www.google.com}
iter=${2:-10}
delay=${3:-.02}

tempdir=$(mktemp -d)
bcin="$tempdir/bcin"  bcout="$tempdir/bcout"  curlout="$tempdir/curlout"
mkfifo       "$bcin"                "$bcout"                  "$curlout"
exec      3<>"$bcin";       exec 4<>"$bcout"
cleanUp() { [ -e "$bcin" ] && rm "$bcin" "$bcout" "$curlout" && rmdir "$tempdir"
            exit;}
trap cleanUp 0 1 2 3 6 15
bc -l <&3 >&4 &
mBc() { echo >&3 "$2"; read -r $1 <&4 ;}
cat >&3 <<EOInitBc
    unit[0]=142;unit[1]=113;unit[2]=115;unit[3]=107;unit[4]=124;unit[5]=120
    define void numfmt (s) {
        if (s==0) { print "0,0\n"; return;};
        p=l(s)/l(1024);
        scale=0;
        p=p/1;
        scale=20;
        print unit[p]," ",s/1024^p,"\n";
    };
    tsiz=0;ttim=0;
EOInitBc

# read variables from curl

checkHttpRes() {
    curl -sm2 -w'%{http_code} %{size_download} %{time_total}' -o/dev/null \
         "$1" >"$curlout" &
    read -r cod siz tim <"$curlout"
    mBc rate "tsiz+=$siz;ttim+=$tim;$siz/$tim;"
    mBc mtim "$tim*1000"
    mBc 'hunit hsz' "numfmt($siz)"
    mBc 'hurt hrat' "numfmt($rate)"
    printf '  %-3s  %7.2f%b %9.2fms %7.2f%b/s\n' "$cod" "$hsz" "\\$hunit" \
           "$mtim" "$hrat" "\\$hurt"
}

# Last part:mainroutine

printf '  %-3s  %8s %11s %10s\n' Res Size Time Rate
i="$iter"
while [ "$i" -gt 0 ];do
    checkHttpRes "$target"
    sleep "$delay"
    i=$((i-1))
done
mBc 'hutsz htsz' "numfmt(tsiz)"
mBc 'huasz hasz' "numfmt(tsiz/$iter)"
mBc ttim "1000*ttim"
mBc atim "1000*ttim/$iter"
mBc 'huart hart' "numfmt(tsiz/ttim)"
printf 'Tot    %7.2f%b %9.2fms\nAvg    %7.2f%b %9.2fms %7.2f%b/s\n' \
       "$htsz" "\\$hutsz" "$ttim" "$hasz" "\\$huasz" "$atim" "$hart" "\\$huart"

Run sample:

$ ./curlStat.sh http://www.google.com 10 .1
  Res      Size        Time       Rate
  200    14.76K    141.84ms  104.09K/s
  200    14.65K    136.21ms  107.53K/s
  200    14.61K    136.74ms  106.86K/s
  200    14.67K    138.08ms  106.26K/s
  200    14.70K    130.56ms  112.56K/s
  200    14.65K    135.72ms  107.97K/s
  200    14.68K    135.28ms  108.53K/s
  200    14.64K    134.20ms  109.07K/s
  200    14.70K    136.32ms  107.82K/s
  200    14.71K    136.19ms  108.00K/s
Tot     146.77K   1361.14ms
Avg      14.68K    136.11ms  107.83K/s

3. Last: bash

This question is tagged sh , but for ((i=... syntax is a bashism. So here is a compact pure bash version of this:

#!/bin/bash
target=${1:-https://www.google.com}  iter=${2:-10} delay=${3:-.02}

txsz(){ local i=$(($1>=1<<50?5:$1>=1<<40?4:$1>=1<<30?3:$1>=1<<20?2:$1>1023?1:0
)) a=(b K M G T P);((i>4?i+=-2:0))&&a=(${a[@]:2})&&set -- $(($1>>20)) $2;local\
r=00$((1000*$1/(1024**i)));printf -v $2 %.2f%s ${r::-3}.${r: -3} ${a[i]};}

declare -i ttim=0 tsiz=0
checkHttpRes() { local code size time ustim hsz hrat
    read -r code size time < <(
      curl -sm2 -w'%{http_code} %{size_download} %{time_total}' -o/dev/null "$1"
    )
    printf -v ustim '%.6f' "$time"
    ustim=$((10#${ustim/.}))
    tsz "$size" hsz
    tsz $(( size*10**7/ustim/10 )) hrat
    ttim+=ustim tsiz+=size ustim=00$ustim
    printf '  %-3s  %8s %9.2fms %8s/s\n' "$code" "$hsz" \
           "${ustim::-3}.${ustim: -3}" "$hrat"
}

printf '  %-3s  %8s %11s %10s\n' Res Size Time Rate
for ((i=iter;i--;)) ;do
    checkHttpRes "$target"
    sleep "$delay"
done

tsz $tsiz htsz
ustim=00$ttim uatim=00$((ttim/iter))
tsz $((tsiz/iter)) hasz
tsz $(( tsiz*10**7/ttim/10  )) hart
printf 'Tot    %8s %9.2fms\nAvg    %8s %9.2fms %8s/s\n' "$htsz" \
       "${ustim::-3}.${ustim: -3}" "$hasz" "${uatim::-3}.${uatim: -3}" "$hart"

Without any fork to bc nor awk , all operation are done in pseudo float using shifted integers.
This will produce same result:

Res      Size        Time       Rate
  200    14.68K    132.79ms  110.55K/s
  200    14.68K    135.59ms  108.24K/s
  200    14.68K    132.31ms  110.99K/s
  200    14.75K    141.66ms  104.15K/s
  200    14.66K    139.90ms  104.79K/s
  200    14.71K    140.07ms  105.00K/s
  200    14.68K    142.74ms  102.86K/s
  200    14.64K    133.42ms  109.71K/s
  200    14.72K    135.62ms  108.56K/s
  200    14.71K    139.16ms  105.72K/s
Tot     146.92K   1373.25ms
Avg      14.69K    137.32ms  106.98K/s
1sbrub3j

1sbrub3j2#

您可以通过awk传输curl输出,并根据需要对其进行格式化,如下所示:

curl -w 'Return Code: %{http_code}; Bytes Received: %{size_download}; Response Time: %{time_total}\n' "https://www.google.com" -m 2 -o /dev/null -s | awk  '{printf "Return Code: %d; KiB Received: %f; Response Time(ms): %f\n", $3, $6/1024, $9*1000}'

因此,一行代码如下:

for ((i=1;i<=50;i++)); do curl -w 'Return Code: %{http_code}; Bytes Received: %{size_download}; Response Time: %{time_total}\n' "https://www.google.com" -m 2 -o /dev/null -s | awk  '{printf "Return Code: %d; KiB Received: %f; Response Time(ms): %f\n", $3, $6/1024, $9*1000}'; done | tee /dev/tty |awk '{ sum += $NF; n++ } END { If (n > 0); print "Average Response Time =",sum /n;}'

您也可以根据需要设置数字的格式,方法是将g,例如%.2f表示2位小数精度,%d表示整数...

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