您在RecyclerView中显示了一个空列表。首先，您在构建时创建了一个空适配器：

// empty list
private var list: ArrayList<LoanRecordModel> = ArrayList()
// adapter created with the empty list
private var loanRecRcvAdapter = LoanRecRcvAdapter(list, this)

然后将该适配器应用到您的RV上：

loanRecRcv.apply{
    ...
    adapter = loanRecRcvAdapter
}

您正在onViewCreated中创建项目列表

list = arrayListOf(
    LoanRecordModel("", "Petty Cash Loan", "12/05/2022", "Open"),
    ...
)

但这是在 * 替换 * 存储在list变量中的列表。之前（在构造时）已经使用原始列表创建了Adapter，所以它仍然在内部使用那个空列表。它没有引用list变量。
两个基本选项-将list设为MutableList并更新其内容而不是替换它：

// empty mutable list - you never need to actually use ArrayLists or whatever
// made it a val so you can't replace it!
private val list = mutableListOf<LoanRecordModel>()
// pass that list object to the adapter, so it's shared
private var loanRecRcvAdapter = LoanRecRcvAdapter(list, this)

...

// update your list contents
list.addAll(listOf(
    LoanRecordModel("", "Petty Cash Loan", "12/05/2022", "Open"),
    ...
))
// notify the adapter that it needs to refresh since its data set (the shared list) has changed
adapter.notifyDataSetChanged()

• 或 *（最好）将新数据传递给适配器，让它在内部存储数据，处理自身更新等：

// in your adapter

// store the current data here - initially an empty list, so it can still display
private var list: List<LoanRecordModel> = emptyList()

fun setData(data: List<LoanRecordModel>) {
    // calling toList makes a new list object - even if the 'data' list object gets
    // modified later, we have our own internal list object that won't be affected
    list = data.toList()
    // update the display however you like
    notifyDataSetChanged()
}

// in your fragment

adapter.setData(listOf(
    LoanRecordModel("", "Petty Cash Loan", "12/05/2022", "Open"),
    ...
))

这种方法更好，因为适配器的数据集是内部保存的，而不是在片段中。您有一个简单的setData函数，它接受新数据，并根据需要处理适配器的更新。调用者不需要知道这些信息。它只传递数据。你也可以从Adapter的构造函数中移除你的List参数--你并没有将它初始化为空列表--这是内部list属性的默认值
顺便说一句，要初始化相同内容的列表，您可以

// create an immutable list
val list = List(5) { LoanRecordModel("", "Petty Cash Loan", "12/05/2022", "Open") }

// or add to a mutable list
list.addAll(List(5) { LoanRecordModel("", "Petty Cash Loan", "12/05/2022", "Open") })

// or another way
repeat(5) {
    list.add(LoanRecordModel("", "Petty Cash Loan", "12/05/2022", "Open"))
}

如果你愿意话