将代码更改为（盲编码）：

public class Fragment_1 extends SherlockFragment {

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState){
    /**
    ** Change the way you get the data. Don't keep references to activities like that.
    **/
    TreeSet<BlacklistWord> theSet =  MainActivity.getInstance().datasource.GetAllWords();
    ArrayList<String> list = new ArrayList<String>();
    for(BlacklistWord i :theSet){
        System.out.println(i.getWord());
        list.add(i.getWord());
    }
    Collections.sort(list);
    View v = inflater.inflate(R.layout.blacklist, container, false);

    listView = view.findViewById(R.id.listview);
    adapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_list_item_1,  list);
    listView.setAdapter(adapter);
    return view;
}
}

您的列表视图没有显示，因为您错误地使用构造函数创建了一个ListView，然后您调用了一个findViewById（它没有任何用处），然后设置了一个适配器，调用了notify data set changed，最后您返回了另一个列表。

使用以下方式：

public class LListFragment extends ListFragment {

    private String[] line;

    public static final String[] TITLES = { "Henry IV (1)", "Henry V",
            "Henry VIII", "Richard II", "Richard III", "Merchant of Venice",
            "Othello", "King Lear" };

    @Override
    public void onActivityCreated(Bundle savedInstanceState) {
        super.onActivityCreated(savedInstanceState);


        ListView listv = getListView();

        setListAdapter(new ArrayAdapter<String>(getActivity(),
                R.layout.scan_row, R.id.textView1, TITLES));
    }
}

或者您在xml中有列表视图，那么..

@Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        // Inflate the layout for this fragment
        View view = inflater.inflate(R.layout.llist_layout, container, false);
        // do your view initialization here
        listv = (ListView) view.findViewById(R.id.lineDlist);
        name = (TextView) view.findViewById(R.id.lineName);
        st = (TextView) view.findViewById(R.id.lineSt);

        listv.setAdapter(new ImageAdapter(getActivity(),
                GeneralClass.lineDetails));

        return view;
    }

因为您正在创建一个新的ListView，并试图在其中找到您的xml listview作为子视图...
而不是用某物作为;

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState){

    View view = inflater.inflate(R.layout.blacklist, container, false);

    ListView listview = (ListView) view.findViewById(R.id.listview);

    //Making BlackList 
    adapter = new ArrayAdapter<String>(getActivity(), android.R.layout.simple_list_item_1,  list);
    listView.setAdapter(adapter);
    ((BaseAdapter) listView.getAdapter()).notifyDataSetChanged();
    container.addView(listView);

    return view;
}

ListView visibilty或正在显示ERROR...请注意，如果您使用扩展ListFragment的片段，请使用listview定义的id（如 list），并按如下方式定义它：android:id="@+id/listview .
并在Fragment类中定义它，如下所示：frgView.findViewById(android.R.id.listview);
如果你仍然有一个问题的可见性的列表视图记住，改变布局的片段与<FragmentLayout>。
是否要在项目中使用将其添加到下。
祝您有一个愉快的编码日...