项目使用Hibernate（JPA），Spring和Maven.my实体和DAO放在一个单独的JAR中。
pom.xml:
<project ...>
...
<artifactId>database</artifactId>
<dependencies>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>3.5.4-Final</version>
</dependency>
</dependencies>
</project>DAO：
public class AbstractDAO<T extends BaseEntity> implements GenericDAO<T> {
private final Class<T> persistentClass;
private EntityManager entityManager;
public AbstractDAO(Class<T> entityClass) {
super();
this.persistentClass = entityClass;
}
@PersistenceContext
public void setEntityManager(EntityManager entityManager) {
this.entityManager = entityManager;
}
public EntityManager getEntityManager() {
return entityManager;
}
...
public void fooBar() {
//Exception from this line
Session session = getEntityManager().unwrap(Session.class);
...
}
....}
我有一个模块，它使用Spring。
pom.xml:
<project ...>
...
<artifactId>api</artifactId>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-orm</artifactId>
<version>${spring.version}</version>
</dependency>
....
</dependencies>
...
</project>AppContext.xml:
<bean id="authService" scope="singleton" class="com.test.management.AuthServiceImpl" />
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" name="EntityManagerFactory">
<property name="persistenceUnitName" value="default"></property>
<property name="dataSource" ref="dataSource"></property>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="generateDdl" value="true" />
<property name="databasePlatform" value="${db.dialect}" />
</bean>
</property>
</bean>
<!-- Values are defined in db.properties -->
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="${db.driver}" />
<property name="url" value="${db.url}" />
<property name="username" value="${db.username}" />
<property name="password" value="${db.password}" />
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" name="TransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory"></property>
</bean>
<tx:annotation-driven />
<bean id="userDAO" scope="singleton" class="com.test.database.dao.impl.UserDAOImpl">
</bean>
<bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" />
</beans>服务项目：
public class AuthServiceImpl implements AuthService {
@Autowired
private UserDAO userDAO;
@Override
public void authorization() {
userDAO.fooBar();
}
}当我尝试从EntityManager获取会话时，我捕获到以下异常：
java.lang.IllegalStateException: No transactional EntityManager available
at org.springframework.orm.jpa.SharedEntityManagerCreator$SharedEntityManagerInvocationHandler.invoke(SharedEntityManagerCreator.java:223)
at $Proxy121.unwrap(Unknown Source)
5条答案
按热度按时间pw9qyyiw1#
您必须使用
@Transactional注解来注解方法：并且，如有必要，例如在使用普通Spring框架时，在Spring的xml配置文件中使用以下声明启用Spring
@Transactional处理（其中txManager是管理器的ID）：tjvv9vkg2#
试试这个？
bweufnob3#
所有这些都对我不起作用，我最终发现问题是我将方法设置为@Transactional，而不是我需要类设置为@Transactional
t5fffqht4#
在我的情况下，这是另一个问题（对于那些谁有问题的@交易）：
c3frrgcw5#
在我的例子中，当我定义自定义方法时，例如findStudentByFirstName，这个异常开始出现。这个问题通过在仓库类中添加@Transactional注解得到了解决。