Hibernate无法Map实体-Query语法异常

qcuzuvrc  于 2022-11-14  发布在  其他
关注(0)|答案(1)|浏览(130)

我正在尝试升级一个旧的遗留WAR应用程序的一些组件，但在升级到Hibernate5.6时遇到了麻烦。Hibernate现在不再能够Map我的用户实体，我不确定为什么。
任何帮助都将不胜感激。如果您需要更多信息，请告诉我。
编辑：添加了HibernateUtil
错误：

com.myapp.hibernate.exception.MyAppHibernateException: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [FROM User WHERE username = :username]
    at com.myapp.hibernate.HibernateManager.getUser(HibernateManager.java:97)
    at com.myapp.servlets.LoginServlet.doPost(LoginServlet.java:46)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:681)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:764)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:227)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:162)
    at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:53)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:189)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:162)
    at com.myapp.filter.SessionFilter.doFilter(SessionFilter.java:61)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:189)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:162)
    at com.myapp.hibernate.HibernateSessionRequestFilter.doFilter(HibernateSessionRequestFilter.java:36)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:189)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:162)
    at com.myapp.filter.PropertiesLoadErrorFilter.doFilter(PropertiesLoadErrorFilter.java:48)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:189)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:162)
    at com.myapp.filter.RequestFilter.doFilter(RequestFilter.java:29)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:189)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:162)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:197)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:97)
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:541)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:135)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:92)
    at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:687)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:78)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:360)
    at org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:399)
    at org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
    at org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:890)
    at org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1789)
    at org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
    at org.apache.tomcat.util.threads.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1191)
    at org.apache.tomcat.util.threads.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:659)
    at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
    at java.lang.Thread.run(Thread.java:750)

失败代码：

public User getUser(String username) throws MyAppHibernateException {
        try {
            Query query = getSession().createQuery("FROM User WHERE username = :username");
            query.setParameter("username", username);
            List<User> users = query.list();
            User user = null;
            if (users.size() > 0)
                user = users.get(0);

            return user;
        } catch (Exception e) {
            logger.error(e.getMessage());
            throw new MyAppHibernateException(e.getMessage());
        }
}

Hibernate.cfg.xml(位于WEB-INF/Class中)

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>
    <session-factory>
        <!-- Database connection settings -->
        <property name="connection.driver_class">org.postgresql.Driver</property>
        <property name="hibernate.transaction.coordinator_class">jdbc</property>

        <property name="dialect">org.hibernate.dialect.PostgreSQL10Dialect</property>
        <property name="show_sql">true</property>
        <property name="current_session_context_class">thread</property>
        
        <!-- Connection pool -->
        <property name="c3p0.min_size">5</property>
        <property name="c3p0.max_size">15</property>
        <property name="c3p0.timeout">300</property>
        <property name="c3p0.max_statements">50</property>
        <property name="c3p0.idle_test_period">3000</property>
        
        <!-- Mapping resource configuration files -->
        <mapping class="com.myapp.hibernate.models.User" /> 
    </session-factory>
</hibernate-configuration>

HibernateUtil

package com.myapp.hibernate;

import org.apache.log4j.Logger;
import org.hibernate.SessionFactory;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.hibernate.cfg.Configuration;
import org.hibernate.service.ServiceRegistry;
import com.myapp.properties.MyProperties;

public class HibernateUtil {

    private static ServiceRegistry serviceRegistry;
    private static final SessionFactory sessionFactory;
    
    private static Logger logger = Logger.getLogger(HibernateUtil.class.getName());

    static {
        try {
            logger.info("Statically initializing Hibernate Session Factory");

            Configuration configuration = new Configuration()
                .setProperty("hibernate.connection.url", MyProperties.getHibernateUrl())                                
                .setProperty("hibernate.connection.username", MyProperties.getHibernateUser())     
                .setProperty("hibernate.connection.password", MyProperties.getHibernatePwd());
            if (MyProperties.getHibernateHbm2ddl_auto() != null) {
                configuration.setProperty("hibernate.hbm2ddl.auto", MyProperties.getHibernateHbm2ddl_auto());
            }
            configuration.configure("hibernate.cfg.xml");
            
            serviceRegistry = new StandardServiceRegistryBuilder().applySettings(configuration.getProperties()).build();
            sessionFactory = configuration.buildSessionFactory(serviceRegistry);
        } catch (Throwable ex) {
            logger.info("Failed to create sessionFactory object. " + ex.getMessage());
            throw new ExceptionInInitializerError(ex);
        }
    }

    public static SessionFactory getSessionFactory() {
        return sessionFactory;
    }
}

用户实体

package com.myapp.hibernate.models;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;

@Entity
@Table(name = "user_")
public class User {
    @Id
    @SequenceGenerator(name = "user_seq", sequenceName = "user_id_seq", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "user_seq")
    @Column(name = "id", unique = true)
    private int identifier;

    @Column(name = "username", unique = true)
    private String username;

    @Column(name = "password")
    private String password;

    @Column(name = "firstName", nullable = false)
    private String firstName;

    @Column(name = "lastName", nullable = false)
    private String lastName;

    public User() {
        super();
    }

    public User(String username, String password, String firstName, String lastName) {
        super();
        this.username = username;
        this.password = password;
        this.firstName = firstName;
        this.lastName = lastName;
    }
}

SQL

CREATE TABLE "public"."user_" (
  "id" int4 NOT NULL,
  "firstname" varchar(255) COLLATE "pg_catalog"."default" NOT NULL,
  "lastname" varchar(255) COLLATE "pg_catalog"."default" NOT NULL,
  "password" varchar(255) COLLATE "pg_catalog"."default",
  "username" varchar(255) COLLATE "pg_catalog"."default",
);
Hibernate

1条答案

按热度按时间
9gm1akwq

9gm1akwq1#

这个问题是由下面的配置引起的(似乎大多数Hibernate教程配置是这样的)

serviceRegistry = new StandardServiceRegistryBuilder().applySettings(configuration.getProperties()).build();
sessionFactory = configuration.buildSessionFactory(serviceRegistry);

它不能在Hibernate5中工作，原因可能是由于服务注册表API更新。
解决办法就是简单地编写它

sessionFactory = configuration.configure("hibernate.cfg.xml").buildSessionFactory();

参考3.8。XML配置文件

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