sqlite 在Django模板中显示用户角色数据

ftf50wuq 于 2022-11-15 发布在 SQLite

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我有一个具有用户角色的Django模型。我希望当另一个用户角色或相同的用户角色登录时，能够在模板之外显示用户角色的First_Name、Last_Name和其他详细信息。
这是我的模特

class User(AbstractUser):
        is_customer = models.BooleanField(default=False)
        is_employee = models.BooleanField(default=False)
        first_name = models.CharField(max_length=100)
        last_name = models.CharField(max_length=100)
        #username = models.CharField(unique = False , max_length=100)
        #email = models.CharField(unique = True , max_length=100 )
        nin = models.IntegerField(unique = False , null=True)
        avatar = models.ImageField(null= True, default="avatar.svg")
        is_landlord = models.BooleanField(default=False)
        objects = UserManager()
        REQUIRED_FIELDS= []
    
    class Landlord(models.Model):
        user = models.OneToOneField(User,related_name="prop_owner", null= True, on_delete=models.CASCADE)
        bio = models.TextField(null=True)
        
        
        USERNAME_FIELD = 'email'
        REQUIRED_FIELDS= []
       
        objects = UserManager()
    
        def __str__(self):
            return str(self.user)

这是我的观点

def propertySingle(
        request,
        pk,
        is_landlord,
    ):
        user = User.objects.get(is_landlord=is_landlord) 
        property = Property.objects.get(id=pk)
        properties = Property.objects.all()
        images = Image.objects.filter(property=property)
        
        context = {
            "property": property,
            "properties": properties,
            "images": images,
            'user':user,
    
        }
       
        return render(request, "base/page-listing-single.html", context)

Template

<div class="sl_creator">
    <h4 class="mb25">Property Owned By:</h4>
        <div class="media">
<img class="mr-3" style="width: 90px; height:90px;" src="{{request.user.avatar.url}}" alt="avatar">
<div class="media-body">
    <h5 class="mt-0 mb0">{{user.last_name}} {{request.user.first_name}}</h5>
    <a class="text-thm" href="#">View other Listings by {{property.landlord.last_name}} {{property.user.is_landlord.first_name}}

sqlite

来源：https://stackoverflow.com/questions/73535188/display-the-data-of-user-role-in-django-template

1条答案

按热度按时间

xoefb8l81#

如果您正在测试当前用户是否为房东，则可以在模板中执行所有这些操作，因为您始终可以参考Request.User User示例来查看谁在访问该页面。

<h4 class="mb25">Property Owned By:</h4>
{% if request.user.is_landlord %}
     ...#show landlord details
{% else %}
    This information only available to landlords

然而，在您看来，您有一个问题。您正在使用GET(返回一条记录)来获取IS_LANDLOWER=True(这将是多个)的所有用户。这将给您一个错误。此外，您可能会对模板中引用的是哪个用户感到困惑，因为默认情况下，您的模板中已经有一个RQUE用户。试试这样的东西

def propertySingle(
    request,
    pk,
):
    # get the property and all info about the landlord
    #now in the template we can access property.landlord with no extra db calls 
    property = Property.objects.get(id=pk).select_related('landlord')
    properties = Property.objects.all()
    images = Image.objects.filter(property=property)
    
    context = {
        "property": property,
        "properties": properties,
        "images": images, 
    }
   
    return render(request, "base/page-listing-single.html", context)

现在，您可以在模板中执行以下操作
模板

<div class="sl_creator">
    <h4 class="mb25">Property Owned By:</h4>
{% if request.user == property.landlord %}
   <!-- the user is THE landlord for this property -->
   You: {{request. user.last_name}}, {{request.user.first_name}}
{% endif %}

{% if request.user.is_landlord %}
   <!-- the user is A landlord, but not necessarily for this property -->
    <div class="media">
        <img class="mr-3" style="width: 90px; height:90px;" src="{{property.landlord.avatar.url}}" alt="avatar">

        <div class="media-body">
    
            <a class="text-thm" href="#">View other Listings by {{property.landlord.last_name}} {{property.landlord.first_name}}
        </div>
    </div>
{% else %}
    <div class="media-body">
    This information only available to landlords
    </div>
{%end if %}

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sqlite 在Django模板中显示用户角色数据

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