Label[] l1 = new Label[30];
DataTable dt = ConsoleApp2.CitiesDB.getCities(this.region);
foreach(DataRow row in dt.Rows)
{
count++;
string city = row.Field<string>("city");
l1[count] = new Label();
l1[count].Location = new System.Drawing.Point(x,y);
l1[count].Size = new Size(140, 80);
l1[count].Font = new System.Drawing.Font("Century Gothic", 8.5F);
l1[count].Text = city;
x = x + 260;
this.Controls.Add(l1[count]);
this.Refresh();
if(count == 4 || count %4 ==0)
{
y = y + 150;
x = 40;
}
//l1[count].Click += new EventHandler(l1_click);
}
所以我做了一个动态标签(每个标签都是一个城市名称)。我如何使每个标签都可点击?我有一个注册表-我想要的是,如果用户点击“纽约”,那么它将出现在“城市”文本框中。与EventHandler的方式不适合我);.我能做什么?我在代码中的意思是不工作:
protected void l1_click(object sender, EventArgs e)
{
RegisterForm register = new RegisterForm(username,email,password,address,phone);
register.state.Text = region;
register.city.Text = l1[count].Text;
register.Show();
}
谢谢(:
1条答案
按热度按时间piv4azn71#
为每个标签指定一个单击事件(动态创建):
在单击事件中,使用
sender
参数查看单击了哪个标签: