我有一个flutter项目，它从Json中的api返回一个数据列表，我想将数据显示为一个特定键的列表，该键是name，但目前我一直收到：

type 'List<dynamic>' is not a subtype of type 'Map<String, dynamic>'

这里是未来的建设者

class HomeScreen extends StatefulWidget {
  const HomeScreen({super.key});
 
  @override
  State<HomeScreen> createState() => _HomeScreenState();
}
 
class _HomeScreenState extends State<HomeScreen> {
  late Future<Workouts_Model> futureWorkouts;
 
  @override
  void initState() {
    super.initState();
    futureWorkouts = APIService.fetchUserWorkout();
  }
...................................
            FutureBuilder<Workouts_Model>(
              future: futureWorkouts,
              builder: (context, snapshot) {
                if (snapshot.hasData) {
                  return Text(snapshot.data!.name ?? 'noname');
                } else if (snapshot.hasError) ;
                print(snapshot.error);
                {
                  return Text('${snapshot.error}');
                }
                return const CircularProgressIndicator();
              },
            ),

下面是api_caller：

static Future<Workouts_Model> fetchUserWorkout() async {
    var url = Uri.parse(Config.apiURL + Config.userWorkoutsAPI);
 
    final response = await http.get(
      url,
      headers: {
        HttpHeaders.authorizationHeader:
            'Token XXXXXXXXXXXXXXX',
      },
    );
 
    final responseJson = jsonDecode(response.body);
    print(responseJson);
 
    if (response.statusCode == 200) {
      return Workouts_Model.fromJson(jsonDecode(response.body));
    } else {
      throw Exception('Failed to load User');
    }
  }

以下是模型：

import 'dart:convert';
 
List<Workouts_Model> workoutsModelFromJson(String str) =>
    List<Workouts_Model>.from(
        json.decode(str).map((x) => Workouts_Model.fromJson(x)));
 
String workoutsModelToJson(List<Workouts_Model> data) =>
    json.encode(List<dynamic>.from(data.map((x) => x.toJson())));
 
class Workouts_Model {
  Workouts_Model({
    required this.id,
    required this.user,
    required this.name,
  });
 
  int id;
  String user;
  String name;
 
  factory Workouts_Model.fromJson(Map<String, dynamic> json) => Workouts_Model(
        id: json["id"],
        user: json["user"],
        name: json["name"],
      );
 
  Map<String, dynamic> toJson() => {
        "id": id,
        "user": user,
        "name": name,
      };
}

如何在模型中显示name的列表，以便在应用程序运行时可以看到它。